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Evgesh-ka [11]
3 years ago
7

How long would it take for a ball dropped from the top of a 484-foot building to hit the ground? round your answer to two decima

l places?
Physics
1 answer:
Alja [10]3 years ago
3 0
First, convert the ft to standard units of meters.
1 foot = <span>0.3048 meters
Therefore,
484 ft = 147.5232 meters

Then, we will use the laws of motion to calculate the time:
x = 0.5 at^2
where:
x is the displacement
a is the gravity (9.8 m/sec^2)
t is the time taken
Substitute in the equation with the givens to calculate the time as follows:
147.5232 = (0.5 x 9.8) t^2
t^2 = 147.5232 / (0.5 x 9.8)
t^2 = 30.11 seconds
t = 5.49</span>
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In one year, a large tree can remove from the air the same amount of carbon dioxide produced by a car travelling 500 miles. If N
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3 years ago
What is the biggest similarity between sports in the United States and sports in other cultures?
leva [86]

Answer:

The first difference is fairly straightforward: other countries prefer other sports. While some aspects of American sports culture are universal there are other things that are sports-specific, such as the 7th-inning stretch at a baseball game or counting the steps of a basketball player after he fouls out.

Explanation:

4 0
3 years ago
Read 2 more answers
Before the experiment, the total momentum of the system is 2.5 kg m/s to the right and the kinetic energy is 5J. After the exper
finlep [7]

Answer:

Option (b) is correct.

Explanation:

Elastic collision is defined as a collision where the kinetic energy of the system remains same. Both linear momentum and kinetic energy are conserved in case of an elastic collision.

Inelastic collision is defined as a collision where kinetic energy of the system is not conserved whereas the linear momentum is conserved. This loss of kinetic energy may due to the conversion to thermal energy or sound energy or may be due to the deformation of the materials colliding with each other.

As given in the problem, before the collision, total momentum of the system is 2.5~Kg~m~s^{-1} and the kinetic energy is 5~J. After the collision, the total momentum of the system is  2.5~Kg~m~s^{-1}, but the kinetic energy is reduced to 4~J. So some amount of kinetic energy is lost during the collision.

Therefor the situation describes an inelastic collision (and it could NOT be elastic).

5 0
3 years ago
I don’t understand how to do this
anzhelika [568]

Explanation:

A) Use Hooke's law to find the spring constant.

F = kx

40 N = k (0.4 m)

k = 100 N/m

B) Period of a spring-mass system is:

T = 2π √(m / k)

T = 2π √(2.6 kg / 100 N/m)

T = 1 s

Frequency is the inverse of period.

f = 1 / T

f = 1 Hz

5 0
3 years ago
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