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Evgesh-ka [11]
3 years ago
7

How long would it take for a ball dropped from the top of a 484-foot building to hit the ground? round your answer to two decima

l places?
Physics
1 answer:
Alja [10]3 years ago
3 0
First, convert the ft to standard units of meters.
1 foot = <span>0.3048 meters
Therefore,
484 ft = 147.5232 meters

Then, we will use the laws of motion to calculate the time:
x = 0.5 at^2
where:
x is the displacement
a is the gravity (9.8 m/sec^2)
t is the time taken
Substitute in the equation with the givens to calculate the time as follows:
147.5232 = (0.5 x 9.8) t^2
t^2 = 147.5232 / (0.5 x 9.8)
t^2 = 30.11 seconds
t = 5.49</span>
You might be interested in
A spherical shell contains three charged objects. The first and second objects have a charge of − 14.0 nC and 31.0 nC , respecti
allsm [11]

Answer:

The charge on the third object is − 21.7nC

Explanation:

From Gauss's Law

Φ = Q/ε₀

where;

Φ is the total electric flux through the shell = − 533 N⋅m²/C

Q is the total charge Q in the shell = ?

ε₀ is the permittivity of free space = 8.85 x 10⁻¹²

From this equation; Φ = Q/ε₀

Q = Φ * ε₀ = − 533 * 8.85 x 10⁻¹²

Q =  −4.7 X 10⁻⁹ C = -4.7nC

Q = q₁ + q₂ + q₃

− 4.7nC = − 14.0 nC + 31.0 nC + q₃

− 4.7nC − 17nC = q₃

− 21.7nC = q₃

Therefore, the charge on the third object is − 21.7nC

8 0
3 years ago
Which of the following statement describes an actual orbit
Leno4ka [110]

I suppose right answer is d because staellite means an object that move around the larger object and Jupiter also moves around the Sun

7 0
3 years ago
Read 2 more answers
We decided to make an iced latte by adding ice to a 200 mL hot latte at 45 °C. The ice starts out at 0 C. How much ice do we nee
tankabanditka [31]

Answer:

m = 77.75 g

Explanation:

Here we know that at equilibrium the temperature of the system will be 10 degree C

so heat given by hot latte = heat absorbed by the ice

now we have

heat given by latte = m s\Delta T

Q_1 = (200)(4.186)(45 - 10)

Q_1 = 29302 J

now heat absorbed by ice is given as

Q_2 = mL + ms\Delta T

Q_2 = m(335 + 4.186(10 - 0))

Q_2 = m(376.86)

now by heat balance we have

Q_1 = Q_2

29302 = m(376.86)

m = 77.75 g

6 0
3 years ago
A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. Its speed is 38 m/s when i
inysia [295]

Explanation:

look !

speed= 38m/s

start from rest= 0

5 0
2 years ago
arzan, who weighs 700 N, swings from a cliff at the end of a convenient vine thatis 20 m long. From the top of the cliff to the
vekshin1

Answer:

= 7.07 m

Explanation:

The Tarzan reaches bottom of swing after descending 2.5 m,

change in his potential energy equals his kinetic energy at bottom of swing

m g h = (1/2) m v²   ,  

hence speed v of Tarzan at bottom of swing is given as  

v = ( 2 g h )1/2

= ( 2 × 9.8 × 2.5 )1/2

= 7 m/s

At the bottom of swing, if the vine breaks, then he is moving with horizontal velocity 7 m/s in gravitational field.  

If vertical distance from ground to bottom of swing is 5 m, then time t for Tarzan to reach ground is given by

S = (1/2)g t2 or   t = (2S/g)1/2

= ( 2 × 5 / 9.8 )1/2

= 1.01 s

Horizontal distance traveled by Tarzan = 1.01 × 7

= 7.07 m

7 0
3 years ago
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