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Evgesh-ka [11]
2 years ago
7

How long would it take for a ball dropped from the top of a 484-foot building to hit the ground? round your answer to two decima

l places?
Physics
1 answer:
Alja [10]2 years ago
3 0
First, convert the ft to standard units of meters.
1 foot = <span>0.3048 meters
Therefore,
484 ft = 147.5232 meters

Then, we will use the laws of motion to calculate the time:
x = 0.5 at^2
where:
x is the displacement
a is the gravity (9.8 m/sec^2)
t is the time taken
Substitute in the equation with the givens to calculate the time as follows:
147.5232 = (0.5 x 9.8) t^2
t^2 = 147.5232 / (0.5 x 9.8)
t^2 = 30.11 seconds
t = 5.49</span>
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Which statement describes a surface wave?
katen-ka-za [31]
A surface wave is a wave that travels along the surface of a medium. The medium is the matter through which the wave travels. Ocean waves are the best-known examples of surface waves. They travel on the surface of the water between the ocean and the air. (According to ck12.org)

So your answer would be A!
5 0
3 years ago
Read 2 more answers
In a chemical reaction, one element replaces another element in a compound to form a new substance. Which of the following best
Andreyy89

Answer:

single replacement

Explanation:

In the question it says one element replaces another element which means there is only one replacement.

3 0
2 years ago
A proton is projected in the positive x direction into a region of a uniform electric field E S 5 126.00 3 105 2 i^ N/C at t 5 0
Dafna11 [192]

Answer:

(a). The magnitude of the acceleration of the proton is 5.74\times10^{13}\ m/s^2

(b). The initial peed of the protion is 2.83\times10^{6}\ m/s

(c). The time is 0.493\times10^{-7}\ sec.

Explanation:

Given that,

Electric field E=-6.00\times10^{5}i\ N/C

Time = 5.0 sec

Distance 7.00 cm

(a). We need to calculate the acceleration

Using formula of force

F=F_{e}

ma=qE

a=\dfrac{Eq}{m}

Where, E = electric field

m = mass of proton

q = charge of proton

Put the value into the formula

a=\dfrac{-6.00\times10^{5}\times1.6\times10^{-19}}{1.67\times10^{-27}}

a=-5.74\times10^{13}\ m/s62

The magnitude of the acceleration of the proton is 5.74\times10^{13}\ m/s^2

(b). We need to calculate the initial peed

Using equation of motion

v^2-u^2=2as

Where, s = distance

Put the value into the formula

0-u^2=2\times(-5.74\times10^{13})\times7.00\times10^{-2}

u=\sqrt{2\times5.74\times10^{13}\times7.00\times10^{-2}}

u=2834783.94

u=2.83\times10^{6}\ m/s

The initial peed of the protion is 2.83\times10^{6}\ m/s

(c). We need to calculate the time interval over which the proton comes to rest

Using formula

t=\dfrac{u}{a}

Where, u = initial velocity

a = acceleration

Put the value into the formula

t=\dfrac{2.83\times10^{6}}{5.74\times10^{13}}

t=0.493\times10^{-7}\ sec

Hence, (a). The magnitude of the acceleration of the proton is 5.74\times10^{13}\ m/s^2

(b). The initial peed of the protion is 2.83\times10^{6}\ m/s

(c). The time is 0.493\times10^{-7}\ sec.

5 0
2 years ago
What is the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m?
notsponge [240]

Answer:

a ) 24 m/s

Explanation:

Given,

Frequency ( f ) = 6 Hz

Wavelength ( λ ) = 4 m

To find : Speed ( v ) = ?

Formula : -

v = f x λ

v

= 4 x 6

= 24 m/s

Therefore, the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m

is 24 m/s.

4 0
3 years ago
Equation of uniformly accelerated motion​
Romashka [77]

This means acceleration a is constant.

Let

a) vo be the initial speed, at t=0

b) v be the final speed after time t

c) d distance travelled in time t

Then we have:

a) v=vo+a×t

b) v²=vo²+2×a×d (Galilei's equation)

c) d=vo×t+a×t²/2

d) average speed vm=(vo+v)/2

3 0
3 years ago
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