When an object gets heated by a temperature ΔT energy needed, E = mcΔT
Here mass of glass = 55 g =
Change in temperature ΔT = 16^0C[/tex] = 16 K
Specific heat of glass = 0.84 J/gK = 840 J/kgK
Substituting we will get
E = *840*16 = 739.2 J
So a heat of 739.2 J is required to raise the temperature of a 55 g glass ball by 16°C
Answer:
See Explanation below.
Explanation:
The electromagnetic spectrum is a range of frequencies spanning a very wide range. Scientists talk about frequencies from about 3 cycles per second to those at least to 10^25 cycles per second. The name for cycles per second is known at Hertz abbreviated to Hz.
Within this spectrum or range exist some of the frequencies we are talk about such as X-Rays, visible light, and wireless transmission including radio waves. However, the range goes beyond what is commonly used at this time both above and below the range.
One example of a portion of electromagnetic spectrum that is very important is the range that is visible to the human eye. This part of the spectrum, with wavelengths in the micrometer range through a few hundred nanometer wavelength range, is known as visible light. The ability to see and use the sense of eye-sight is dependent on this portion of the electromagnetic spectrum.
Another example of the electromagnetic spectrum that is well known has to do with radio waves. This part if from about 3 MHz up to about 300 GHz. Within this portion of the electromagnetic spectrum are radio and television transmissions and receptions. Also wireless phones, wireless Internet, and satellite transmission and reception are included in this portion of the electromagnetic spectrum.
Answer:
As I know it is in Jupiter the objects weight more than 2x than on Earth.
Please give me 5* if this was helpful. :)
Answer:
-35 m/s
Explanation:
Momentum is conserved.
Momentum before firing = momentum after firing
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Before the bullet is fired, the bullet and rifle have no velocity, so u₁ and u₂ are 0.
0 = m₁v₁ + m₂v₂
Given m₁ = 0.7 kg, v₁ = 350 m/s, and m₂ = 7 kg:
0 = (0.7 kg) (350 m/s) + (7 kg) v
v = -35 m/s
The rifle recoils at 35 m/s in the opposite direction.