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2 years ago

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A worker does 25 J of work lifting a bucket, then sets the bucket back down in the same place. What is the total net work done o

n the bucket?

1 answer:

Vera_Pavlovna [14]2 years ago

5 0

Answer:

0 J

Explanation:

As work is force times displacement, if no displacement occurs, no work occurs.

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The difference in energy on either side of the wheel is a measure of the wheel’s ___________.

atroni [7]

I believe the answer is potential difference

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2 years ago

If you have 3 equal plates hanging 2 spaces from the center of a balance, at what distance would you need to place 2 equal plate

Reptile [31]

You answere would be C. 3 spaces

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2 years ago

A uniform solid disk of mass 5.00 kg and diameter 47.0 cm starts from rest and rolls without slipping down a 40.0 ∘ incline that

saveliy_v [14]

Answer:

The speed it reaches the bottom is

$v=6.51m/s$

Explanation:

Given: $m=5.0kg$ , $r=47cm\frac{1m}{100cm}=0.47m$

Using the conservation of energy theorem

$U_i=K_E+K_{ER}$

$m*g*h=\frac{1}{2}*m*v^2+\frac{1}{2}*I*w^2$

$v=r*w$ , $I=\frac{1}{2}*m*r^2$

$m*g*h=\frac{1}{2}*m*(r*w)^2 +\frac{1}{2}*[\frac{1}{2} *m*r^2]*w^2$

$m*g*h=\frac{3}{4}*m*r^2*w^2$

$g*h=\frac{3}{4}*r^2*w^2$

Solve to w'

$w^2=\frac{4*g*h}{3*r^2}$

$h=x*sin(30)=6.5m*sin(30)=3.25m$

$w=\sqrt{\frac{4*9.8m/s^2*3.25m}{3*(0.235m)^2}}$

$w=27.74rad/s$

$v=27.74rad/s*0.235m=6.51m/s$

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3 years ago

True or false a solid object can cast a shadow

elena55 [62]

That would be true because a solid object can cast a shadow

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2 years ago

Read 2 more answers

what is the force if a block of wood with mass 20 kg slides along a frictionless surface at 2 m/s squared

CaHeK987 [17]

Answer:

40 N

Explanation:

F=ma where F is the applied force, m is the mass of object and a is the acceleration.

Since there is no friction, substituting 20 Kg for m and 2 m/s squared for a then we obtain

F=20*2=40 N

5 0

3 years ago