Chemical change because your changing one form to another
Stereochemistry, a subdiscipline of chemistry, involves the study of the relative spatial arrangement of atoms that form the structure of molecules and their manipulation.
<h3>What is the use of stereochemistry?</h3>
Using stereochemistry, chemists can work out the relationships between different molecules that are made up from the same atoms. They can also study the effect on the physical or biological properties these relationships give molecules.
<h3>Why is it called stereochemistry?</h3>
The term “stereochemistry” is derived from the Greek “stereos” meaning solid—it refers to chemistry in three dimensions. Since nearly all organic molecules are three dimensional (with the exception of some olefins and aromatics to be discussed later), stereochemistry cannot be considered a branch of chemistry.
Learn more about stereochemistry here:
<h3>
brainly.com/question/13266152</h3><h3 /><h3>#SPJ4</h3>
<span>B. astreoids, comets, and meteors
All of these are smaller than planets
</span>
Answer:
The C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule
Explanation:
Isotopic labeling is a common method for deducing reaction mechanism in chemistry.
In photosynthesis, the oxygen in the found in Glyceraldehyde-3-Phosphate comes from the carbon dioxide, This is also finally found in the glucose produced at the end of the cycle.
The oxygen in water is released into the atmosphere as the oxygen molecule.
Therefore, the C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule.
Answer:
203 grams
Explanation:
<em>It is known that 1.0 mole of a compound contains Avogadro's number of molecules (6.022 x 10²³).
</em>
<em><u>Using cross multiplication:</u></em>
1.0 mol contains → 6.022 x 10²³ molecules.
??? mol contains → 7.2 x 10²⁴ molecules.
∴ The no. of moles of (6.3 x 10²⁴ molecules) of NH₃ = (1.0 mol)(7.2 x 10²⁴ molecules)/(6.022 x 10²³ molecules) = 11.96 mol.
<em>∴ The no. of grams of NH₃ present = no. of moles x molar mass </em>= (11.96 mol)(17.0 g/mol) = <em>203.3 g ≅ 203.0 g.</em>