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Margaret [11]
3 years ago
7

What classification of alcohol would be synthesized from the reaction of 2-butanone with a Grignard reagent? From the reaction o

f butanal with a Grignard reagent?A. A secondary alcohol; a secondary alcoholB. A tertiary alcohol; a secondary alcoholC. A secondary alcohol; a primary alcoholD. A tertiary alcohol; a primary alcohol
Chemistry
2 answers:
r-ruslan [8.4K]3 years ago
8 0

Answer:

B. A tertiary alcohol; a secondary alcohol

Explanation:

Grignard reagent has a formula RMgX where X is a halogen, and R is an alkyl or aryl group.

Grignard reagent reacts with aldehydes and ketones to form alcohol. However the classification (that is; Primary, secondary and tertiary)  varies depending on which it reacts with.

2-butanone is a ketone.

Ketones reacts with Grignard reagent to form tertiary alcohol

Butanal is an aldehyde.

Aldeyde reacts with grignard reagent to form Secondary alcohol

The answer is; Tertiary alcohol; Secondary alcohol

mart [117]3 years ago
7 0

Answer:

It takes 30 minutes to feel the effects of alcohol.

Explanation:

It may take an hour to metabolize a drink, but it takes approximately thirty minutes before you feel alcohol's effects. This is a good gauge for pacing yourself. Drinking more than one drink every 30 minutes means you are probably drinking too much, too fast.

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Which of the following statement is not true about cooking techniques? 
nika2105 [10]

Answer:

b) Every experienced cooks at home tend not to use recipes, instead based entirely upon their knowledge of cooking technique.

Explanation:

This is because even the most experienced cooks might make a mistake, so having a recipe where they can follow is better than just use their knowledge. If his or her knowledge has a mistake it might create a big consequence.

8 0
3 years ago
Calculate the molecular mass of the nonionic solutes.
3241004551 [841]

Answer:

The molecular mass of the nonionic solutes is 124,90 g/m

Explanation:

This is the formula for boiling point elevation.

ΔT = Kb . m

Where ΔT = Tb (solution) - Tb (pure solvent)

Where Kb = the ebullioscopic constant

Where m = molality (moles of solute in 1kg of solvent)

Kb for water is 0,512°C/molal

100,680°C - 100°C = 0,512°C/molal . m

0,680°C = 0,512°C/molal . m

0,680°C /0,512 molal/°C = m

1,32 molality (This are my solute moles in 1kg (1000g) of solvent but I have just 390 g, so let's build the rule of three)

1000 g _____ 1,32 moles

390 g ______ (3,90 g . 1,32 moles) / 1000 g = 0,5148 moles

Molecular mass = g/ mol (mass/moles)

64,3 g /0,5148 moles = 124,90 g/m

8 0
3 years ago
Given the enthalpies of reaction below, determine the enthalpy change for the reaction: N2O (g) + NO2 (g) 3NO (g). N2 (g) + O2 (
lubasha [3.4K]
This problem applies Hess' Law to come up with the final reaction from a series of reactions given. Equation (1) stays as it is. Equation (2) should be inverted and divided by 2. Equation (3) is simply divided by 2. The energies should also correspond to the operations. Adding the net energies of each reaction, the total energy is 155.65 kJ. Hence, the answer is A.
6 0
3 years ago
How many moles of N2 are needed to make 5.0 moles of NH3?
Juli2301 [7.4K]

Answer:

The answer is "2.5 mole"

Explanation:

The reaction for producing NH_3 can be defined as follows:

Reaction:

N_2+ 3H_2 \rightarrow 2NH_3

According to the above reaction, to produce 2 moles of NH_3  we need 1 mole of nitrogen:

So, according to the question to produce 5.0 mole NH_3 the required N_2:

\Rightarrow \ 5.0 \ mole \ of \ NH_3  \times  \frac{1 \ mole\ of \ N_2}{2 \ mole \ of NH_3}\\\\\Rightarrow 5.0 \times \frac{1}{2}\\\\\Rightarrow 2.5\  mole\\

To produce 5.0 mole NH_3  we need 2.5 mole N_2

5 0
3 years ago
The attraction between oppositely charged ions is called
Irina18 [472]
Its called ionic bonding! :^)
3 0
3 years ago
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