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kirza4 [7]
3 years ago
5

I’ll mark you as brinlist please help.

Physics
2 answers:
Ede4ka [16]3 years ago
8 0

Answer:

245 divided by 5.14=47.6653696 or 47.66

Explanation:

Lesechka [4]3 years ago
6 0
47.6653 is the correct answer
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Hii please help i’ll give brainliest!!
den301095 [7]

Answer:

C

Explanation:

6 0
2 years ago
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the apparent weight of a body wholly immersed in water is 32N and its weight in 96N and calculate volume of the body
ArbitrLikvidat [17]

Answer:

0.0065 m³

Explanation:

Apparent weight = weight − buoyancy

32 N = 96 N − (1000 kg/m³) (9.8 m/s²) V

V = 0.0065 m³

3 0
3 years ago
What length of tube would be required to produce a second tone under the same experimental conditions? Explain your answer.
Alisiya [41]

There is an indirect relationship between length and frequency. The longer the length the pipe has, the higher frequency it is. The shorter the length the pipe has, the lower frequency it is.

<u>Explanation:</u>

The four properties of the string that affect its frequency are length, diameter, tension, and density. These properties are described below: When the length of a string is changed, it will vibrate with a different frequency. Shorter strings have higher frequency and therefore higher pitch.

The longer the tube is the lower the pitch of the note that it can emit. When a tube is heated it expands and so is longer! As the gas in the tube gets warmer the molecules move faster, that means they can carry the vibrations of the sound wave more rapidly and so the pitch goes up.

7 0
3 years ago
In noisy factory environments, it's possible to use a loudspeaker to cancel persistent low-frequency machine noise at the positi
Vaselesa [24]

Answer:

7.39 m or 3.61 m

Explanation:

\lambda = Wavelength

f = Frequency = 90 Hz

v = Speed of sound = 340 m/s

Path difference of the two waves is given by

s_1-s_2=\frac{\lambda}{2}

Velocity of wave

v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{340}{90}\\\Rightarrow \lambda=3.78\ m

s_1=s_2\pm\frac{\lambda}{2}\\\Rightarrow s_1=5.5\pm \frac{3.78}{2}\\\Rightarrow s_1=7.39\ m, 3.61\ m

So, the location from the worker is 7.39 m or 3.61 m

7 0
3 years ago
One Newton is equivalent to<br> A. 1 kg/s2<br> B. 1 kg*m/s<br> C. 1 kg*m/s2<br> D. 1 kg/s
tiny-mole [99]

Answer:

B

Explanation:

7 0
2 years ago
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