The answer is no because after each 3 there is one more zero added
to be repeating the number of zeros would have to stay the same
Obtuse because it only takes one obtuse angle to make an obtuse triangle
The solution of the inequality is -8 ≥ b, and the correct graph is the one in option D.
"number line with a closed circle plotted at negative eight and arrow pointing left."
<h3>
How to solve the inequality?</h3>
Here we have the inequality:
-0.8*b + 2.3 ≥ 8.7
And we want to solve this, to do so, we need to isolate the variable b in one of the sides of the inequality.
-0.8*b + 2.3 ≥ 8.7
2.3 - 8.7 ≥ 0.8*b
-6.4 ≥ 0.8*b
-6.4/0.8 ≥ b
-8 ≥ b
So the solution is the set of all numbers equal to or smaller than -8, then the correct graph will be the one described by D.
Learn more about inequalities:
brainly.com/question/24372553
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Answer: Y = 3x - 2
Work: Okay, let's take this step by step. Since the Y - Intercept is -2, put a dot on -2 on the (Y) Line. It also just so happens that the line goes through -2. Now with 3x. 3x is the same thing as 3x / 1. Since three is on the top, you go up three from -2, and then move over one spot because of the 1 (If it was a negative one, you go the opposite direction) Alright, now you see that the line also passes through that point as well, so it has to be y = 3x -2
<em>I hope this helps, and Happy Holidays! :)</em>
Answer:
As per the question, we need to convert product of sum into sum of product,
Given:
(A' +B+C')(A'+C'+D)(B'+D'),
At first, we will solve to parenthesis,
= (A'+C'+BD) (B'+D')
As per the Rule, (A+B)(A+C) = A+BC, In our case if we assume X = A'+C', then,
(A' +B+C')(A'+C'+D) = (A'+C'+B)(A'+C'+D) = (A'+C'+BD)
Now,
= (A'+C'+BD) (B'+D') = A'B' + A'D' + C'B' +C'D' +BDB' +BDD"
As we know that AA' = 0, it mean
=A'B'+A'D'+C'B'+C'D'+D*0+B0
=A'B'+A'D'+C'B'+C'D' as B * 0 and D*0 = 0
Finally, minimum sum of product boolean expression is
A''B'+A'D'+C'B'+C'D'
=
