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3 years ago

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The mass of a string is 7.7 × 10-3 kg, and it is stretched so that the tension in it is 190 N. A transverse wave traveling on th

is string has a frequency of 300 Hz and a wavelength of 0.80 m. What is the length of the string?

1 answer:

Scilla [17]3 years ago

3 0

Length of the strings = 2.33 m

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A 2.0-kilogram ball rolls down a ramp. if the ball accelerates at a rate of 12 m/s2, the net force causing the acceleration is:

ehidna [41]

Answer:

D

Explanation:

f = ma

2 x 12 = 24

answer could differ since it's rolling down a ramp. if an angle is given our approach differs.

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2 years ago

Calculate the number of moles of water molecules in 12 dm' of water<br>vapour at STP.<br><br>

Vinvika [58]

Answer:

$22.4 \: {dm}^{3} \: are \: occupied \: by \: 1 \: mole \\ 12 \: {dm}^{3} \: will \: be \: occupied \: by \: ( \frac{12}{22.4} ) \: moles \\ = 0.536 \: moles$

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3 years ago

If the current in this circuit is 3 A, what must be the value of R3?<br><br><br>It's 5 Ω

Svetllana [295]

Explanation :

It is given that,

In the given figure all the three resistors are in series.

Current flowing in the circuit, $I=3\ A$

Voltage, $V=30\ V$

We know that in series circuit the current flowing in all resistors is same.

Using Ohm's law, we get:

$V=IR$

$30\ V=3\ A(2\ \Omega+3\ \Omega+R_3)$

$R_3=5\ \Omega$

Hence, this is the required solution.

5 0

3 years ago

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Consider a 2 m wide and 5 m long slab resting on flat, fixed, earthen bed. The slab is 20 cm thick with uniform properties. You

4vir4ik [10]

Answer:

Explanation:

The coordinate sketch for the system is shown in the attached file below. Also, in the cartesian coordinate system, since the height is less than the length and width, we did neglect the height. Thus, we eliminate the height and converted it to a two-dimension.

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3 years ago

The temperatureTdin degrees Fahrenheit in terms of the Celsius temperaturedis given by=Td+9/5d+32.The temperatureCvin degrees Ce

Shalnov [3]

Answer:

$T_F=\frac{9}{5}(T_K-273)+32$

Explanation:

Since the temperature in degrees Fahrenheit in terms of the Celsius is given by the formula $T_F=\frac{9}{5}T_C+32$ and the temperature in degrees Celsius in terms of the Kelvin temperature is given by the formula $T_C=T_K-273$ , we can use the second formula and substitute it straight into the first formula (since a simplification is not being asked), obtaining $T_F=\frac{9}{5}(T_K-273)+32$ .

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3 years ago