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vfiekz [6]
2 years ago
6

what is the vapor pressure of water if the total vapor pressure is 1.5 atm and the pressure of oxygen is 0.2 atm?

Physics
1 answer:
andreyandreev [35.5K]2 years ago
8 0

Since the total pressure of each gas is the sum of the partial pressures of all the individual gases, the vapor pressure of oxygen is  1.3 atm.

From Dalton's law of partial pressure, the total pressure is the sum of the individual partial pressures of the gases;

PT = PA + PB + PC + --------

Given that;

Vapor pressure of oxygen = 0.2 atm

Total pressure = 1.5 atm

Vapor pressure of oxygen = ?

Partial pressure of oxygen =  1.5 atm - 0.2 atm = 1.3 atm

The vapor pressure of oxygen is  1.3 atm.

Learn more: brainly.com/question/2510654

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At Alpha Centauri's surface, the gravitational force between Alpha Centauri and a 2 kg mass of hot gas has a magnitude of 618.2
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Answer:

6.86 * 10^8 m

Explanation:

Parameters given:

Mass of hot gas, m = 2 kg

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Mass of Alpha Centauri, M = 2.178 * 10^30 kg

The gravitational force between two masses (the hot gas and Alpha Centauri) , m and M, at a distance, r, given as:

F = (G*M*m) / r²

Where G = gravitational constant

Therefore,

618.2 = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / r²

=> r² = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / 618.2

r² = 4.699 * 10^17 m²

=> r = 6.86 * 10^8 m

We are told that the hot gas is on the surface of Alpha Centauri, hence, the distance between both their centers is the radius of Alpha Centauri.

The mean radius of Alpha Centauri is 6.86 * 10^8 m.

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Rewriting our equation:

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