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3 years ago

PLEASE HELP MY ASSIGNMENT IS DUE IN 3 HOURS!!!!

Mathematics

1 answer:

dybincka [34]3 years ago

8 0

Answer:

8.9 Feet

Step-by-step explanation:

a^2+b^2 = c^2

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Find the x- and y-intercept of the line.<br><br> x + 4y = 36? help

zavuch27 [327]

<span>Simplifying X + 4y = 36 Solving X + 4y = 36 Solving for variable 'X'. Move all terms containing X to the left, all other terms to the right. Add '-4y' to each side of the equation. X + 4y + -4y = 36 + -4y Combine like terms: 4y + -4y = 0 X + 0 = 36 + -4y X = 36 + -4y Simplifying X = 36 + -4y</span>

3 0

3 years ago

Read 2 more answers

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

4 years ago

Kenneth is making chocolate cakes. For each cup of milk he uses 1 3/4 cups of flour. For each cup of flour he uses, he needs to

Ad libitum [116K]

1 cup milk= 1 3/4 cup flour
1 cup flour=3/7 cup cocoa

4cups milk= 4x 1 3/4=7 cups flour
7 cups flour= 7x3/7= 3 cups cocoa

So the answer would be 3 cups of Cocoa

5 0

4 years ago

What’s the range of ()=−4|−2|−3

Tpy6a [65]

Answer:

Step-by-step explanation:

4 0

3 years ago

I don't understand how to get the answer to problem 9

andrew-mc [135]

I see the cosine in problem 7 and I see the cotangent in problem eight. So I know that you're talking about trig functions in class. Problem 9 is trying to find out if you know what they're good for. You have a right triangle and you know the lengths of all three sides. So you can easily find the sine or the cosine or the tangent or the cotangent of the angle. Pick one and calculate the number. Then use your calculator to find the angle that has that number for the trig function that you chose.

7 0

3 years ago