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3 years ago

How can hand tools help every technician for their safety in doing hard servicing activities

Physics

1 answer:

Anni [7]3 years ago

5 0

Answer: Hand tools are necessary for daily activities.

Explanation:

The hand tools are useful for day to day activities they aid in pouring substances, holding things, mixing substances, cleaning and for other purposes. In a chemical laboratory the hand tools like test tube holders can help in holding the chemicals. In a medical laboratory the forceps can be useful in holding and cutting the sections without causing any harm to the hands. Hand tools avoid the direct contact with the microorganisms in medical laboratory thus protect against infections. Hand tools aid in surgical operations and they help in avoiding direct contact with the blood vessels and organs preventing contamination and infections.

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3. What is the mass of a sample of alcohol (Specific heat = 2445 J/kg °C.) If it requires

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3 years ago

An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a ra

lukranit [14]

Answer:

$\frac{dA}{dt} = 28800 \ m^2/year$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Geometry

Area of a Rectangle: A = lw

Algebra I

Exponential Property: $w^n \cdot w^m = w^{n + m}$

Calculus

Derivatives

Differentiating with respect to time

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Explanation:

Step 1: Define

Area is A = lw

2w = l

w = 300 m

$\frac{dw}{dt} = 24 \ m/year$

Step 2: Rewrite Equation

Substitute in l: A = (2w)w
Multiply: A = 2w²

Step 3: Differentiate

Differentiate the new area formula with respect to time.

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Simplify: $\frac{dA}{dt} = 4w\frac{dw}{dt}$

Step 4: Find Rate

Use defined variables

Substitute: $\frac{dA}{dt} = 4(300 \ m)(24 \ m/year)$
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3 0

3 years ago

Read 2 more answers

Two masses 1.2kg and 1.8kg are connected to the ends of a rod of length 2m. Find the moment of inertia about the axes, 1)going t

frutty [35]

Answers: 1) 3 kg m²

2) 2.88 kg m²

Explanation: Question 1

I = m(r)²+ M(r)²

I = 1.2 kg × (1 m )² +1.8 kg ×(1 m )²

∴ I = 3 kg m²

Question 2

ACCORDING TO THE DIAGRAM DRAWN FOR QUESTION 2

we have to decide where the center of gravity (G) lies and obviously it should lie somewhere near to the greater mass. (which is 1.8 kg). Since we don't know the distance from center of gravity(G) to the mass (1.8 kg) we'll take it as 'x' and solve!!

moments around 'G'

F₁ d ₁ = F₂ d ₂

12 (2-X) = 18 (X)

24 -12 X =18 X

∴ X = 0.8 m

∴ ( 2 - x ) = 1.2 m

∴ Moment of inertia (I) going through the center of mass of two masses,

⇒ I = m (r)² +M (r)²

⇒ I = 1.2 × (1.2)² + 1.8 × (0.8)²

⇒ I = 1.2 × 1.44 + 1.8 × 0.64

⇒ I = 1.728 + 1.152

⇒ ∴ I = 2.88 kg m²

∴ THE QUESTION IS SOLVED !!!

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3 years ago

How can hand tools help every technician for their safety in doing hard servicing activities​

How can hand tools help every technician for their safety in doing hard servicing activities