Answer:
7. 3–ethyl–6 –methyldecane
8. 5–ethyl–2,2–dimethyl–4–propyl–4 –heptene
Explanation:
It is important to note that when naming organic compounds having two or more different substituent groups, we simply name them alphabetically.
The name of the compound given in the question above can be written as follow:
7. Obtaining the name of the compound.
Compound contains:
I. Decane.
II. 3–ethyl.
III. 6 –methyl.
Naming alphabetically, we have
3–ethyl–6 –methyldecane
8. Obtaining the name of the compound.
Compound contains:
I. 2,2–dimethyl.
II. 4–propyl.
III. 4 –heptene.
IV. 5–ethyl.
Naming alphabetically, we have
5–ethyl–2,2–dimethyl–4–propyl–4 –heptene
the answer is a because the positive cations are attracted to the negative cathode. when the positive ions get to the cathode they pick up an electron and this produces normal sodium.
The formula of acetic acid is CH3COOH => C2H4O2.
So, the acetic acid has the same number of atoms of carbon (C) than of oxygen (O).
Therefore, the sample that contains 96.5 moles of carbon, will contain also 96.5 moles of O.
Answer: 96.5 moles of oxygen.
The volume of the 18M HCl needed to make the solution will be 2.5 mL.
<h3>Dilution</h3>
According to the dilution principle, the number of moles of solutes in a solution before and after dilution must remain the same.
Since, mole = molarity x volume
Thus, molarity x volume before dilution = molarity x volume after dilution.
Mathematically, the equation is written as: m1v1 = m2v2
In this case, m1 = 18 M, m2 = 1.5 M, and v2 = 30 mL.
What we are looking for is v1, the amount of the stock HCl needed for dilution.
v1 = m2v2/m1 = 1.5 x 30/18 = 2.5 mL.
Thus, 2.5 mL of the stock HCl would be needed.
More on dilution can be found here: brainly.com/question/21323871
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