The answer is B. molality
Answer : The rate for a reaction will be 
Explanation :
The balanced equations will be:
In this reaction, 
and 
are the reactants.
The rate law expression for the reaction is:
![\text{Rate}=k[A]^2[B]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D%5E1)
or,
![\text{Rate}=k[A]^2[B]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D)
Now, calculating the value of 'k' by using any expression.
Now we have to calculate the initial rate for a reaction that starts with 1.48 M of reagent A and 1.32 M of reagents B.
![\text{Rate}=k[A]^2[B]^0[C]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D%5E0%5BC%5D%5E1)
Therefore, the rate for a reaction will be
Answer:
US₂
Explanation:
Uranium sulfide (US₂)
Uranium atomic symbol = U
Sulfur atomic symbol = S
Uranium valency = +4
Sulfur valency = -2
So;
Uranium sulfide (US₂)
Respuesta:
4.42 × 10⁻⁶ m³
Explicación:
Paso 1: Información provista
- Densidad del osmio (ρ): 22600 kg/m³
Paso 2: Convertir 100 g a kilogramos
Usaremos el factor de conversion 1 kg = 1000 g.
100 g × 1 kg/1000 g = 0.100 kg
Paso 3: Calcular el volumen ocupado por 0.100 kg de osmio
La densidad es una propiedad intensiva, igual al cociente entre la masa y el volumen.
ρ = m/V
V = m/ρ
V = 0.100 kg / (22600 kg/m³) = 4.42 × 10⁻⁶ m³
Answer:
C. Al
Explanation:
2Al+ 3H2SO4(l)------> Al2(SO4)3+ 3H2
