Can someone help me with this prooblem
1 answer:
Answer:
9.85
Step-by-step explanation:
I hate these, LOL
We're going to draw a triangle on the graph paper to solve this. (in theory)
The top point is at 2 on the x axis, and the bottom is at 6. That's a difference of 4. Draw a line from the top dot over 4 spaces, so a line dropped from there could go straight to the bottom dot. We'll call this line/side of the triangle a, and a = 4.
Then we drop the line from there (6, 4) down to the second dot at (6, -5). That line is 9 places long. We'll call this line/side of the triangle b, and b = 9.
(This is so much easier to draw than type, I'll attach a picture).
Then we connect the two dots diagonally to form line/side c of our triangle. This is the length we don't know.
The pythagorean theorem says a^2 + b^2 = c^2
So a = 4, b = 9, c is unknown for our triangle
(4)(4) + (9)(9) = c^2
16 + 81 = 97
The square root of 97 = 9.8488, so if they have you round, I would say 9.85
Sorry if this just confused you more.
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Asked and answered elsewhere.
brainly.com/question/9247314
You obviously don't mind using "technology" (Brainly) to answer these questions. A graphing calculator can do quadratic regression on the sequence and tell you its formula.
If you want to do it by hand, you can write the equation
.. y = ax^2 +bx +c
and substitute three of the given points. Then solve the resulting three linear equations for a, b, and c.
.. 4 = a +b +c
.. 7 = 4a +2b +c
.. 12 = 9a +3b +c
Subtracting the first equation from the other two reduces this to
.. 3 = 3a +b
.. 8 = 8a +2b
The latter can be divided by 2, so reduces to
.. 4 = 4a +b
Subtracting the first of the reduced equations from this, you have
.. 1 = a
so
.. 3 = 3*1 +b
.. 0 = b
and
.. 4 = a + b + c = 1 + 0 + c
.. 3 = c
And your equation is
.. y = x^2 +3 . . . . . . as shown previously
brainly.com/question/9247314
You obviously don't mind using "technology" (Brainly) to answer these questions. A graphing calculator can do quadratic regression on the sequence and tell you its formula.
If you want to do it by hand, you can write the equation
.. y = ax^2 +bx +c
and substitute three of the given points. Then solve the resulting three linear equations for a, b, and c.
.. 4 = a +b +c
.. 7 = 4a +2b +c
.. 12 = 9a +3b +c
Subtracting the first equation from the other two reduces this to
.. 3 = 3a +b
.. 8 = 8a +2b
The latter can be divided by 2, so reduces to
.. 4 = 4a +b
Subtracting the first of the reduced equations from this, you have
.. 1 = a
so
.. 3 = 3*1 +b
.. 0 = b
and
.. 4 = a + b + c = 1 + 0 + c
.. 3 = c
And your equation is
.. y = x^2 +3 . . . . . . as shown previously