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3 years ago

A karyotype can be used to determine the number of ____________________ (alleles, chromosomes) in a person’s cells.

Chemistry

1 answer:

Furkat [3]3 years ago

5 0

Answer:

Chromosomes

Explanation:

A karyotype is an individual's collection of chromosomes

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Jayla

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We can change a gas to liquid by_________ the temperature and_________

Tpy6a [65]

Decreasing, Removing

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3 years ago

What is the density of a 700 kg object with a volume of 649 m3? (Density: D = ) 0.927 kg/m3 .4543 kg/m3 1.079 kg/m3 4.543 kg/m3

alekssr [168]

The answer to your question is the third option "1.079 kg/m3
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3 years ago

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In laboratory experiment, a NOVDEC Student was

Ede4ka [16]

Answer:

i. Molar mass of glucose = 180 g/mol

ii. Amount of glucose = 0.5 mole

Explanation:

The volume of the glucose solution to be prepared = 500 $cm^3$

Molarity of the glucose solution to be prepared = 1 M

i. Molar mass of glucose ( $C_1_2H_6O_6$ ) = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol

ii. mole = molarity x volume. Hence;

amount (in moles) of the glucose solution to be prepared

= 1 x 500/1000 = 0.5 mole

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3 years ago

What does the number 18.9984 represent in the image?

Yanka [14]

The element symbol in chemistry comprises atomic number and mass number.

Atomic number is written on the top of element and mass number is written at the bottom.

For eg:

If Y is an element that is having atomic number a and mass number x. Then its denotion will be:

ᵃYₓ.

So here ⁹F₁₈.₉₉

Here 18.99 will denote mass number while 9 will denote atomic number.

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3 years ago

Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict wheth

Elena-2011 [213]

Answer:

$\Delta S_{surr} = + 0.32113\: kJ/K$

Explanation:

Given: Entropy of surrounding: ΔSsurr = ?

Temperature: T= 355 K

The change in enthalpy of reaction: ΔH = -114 kJ

Pressure: P = constant

As we know, ΔH = -114 kJ ⇒ negative

Therefore, the given reaction is an exothermic reaction

Therefore, Entropy of surrounding at constant pressure is given by,

$\Delta S_{surr} = \frac{-\Delta H}{T}$

$\therefore \Delta S_{surr} = -\left (\frac{-114 kJ}{355 K} \right ) = + 0.32113\: kJ/K > 0$

In the given reaction:

2NO(g) + O₂(g) → 2NO₂(g)

As, the number of moles of gaseous products is less than the number of moles of gaseous reactants.

$\therefore \Delta S_{system} < 0$

As we know, for a spontaneous process, that the total entropy should be positive.

$\Delta S_{total} = \Delta S_{surr} + \Delta S_{system} > 0$

Therefore, at the given temperature,

if $\Delta S_{surr} > \Delta S_{system} \Rightarrow \Delta S_{total} > 0$ then the given reaction is spontaneous

if $\Delta S_{surr} < \Delta S_{system} \Rightarrow \Delta S_{total} < 0$ then the given reaction is non-spontaneous

6 0

3 years ago