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Ad libitum [116K]
3 years ago
10

How would the calculated concentration of the hci be affected if the sodium hydroxide were poured from ma beaker that contained

some water before the naoh were added to it
Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, the beaker that contained some water before NaOH were added means that the resulting solution in that beaker will be more dilute. When this diluted sodium hydroxide solution is added to HCl (not hci), the reaction below occurs

HCl + NaOH ⇒ NaCl + H₂O

The reaction above is a neutralization reaction. <u>The concentration of the acid (HCl) will reduce when a base (sodium hydroxide) is added and will also reduce more because of the presence of more water (in the base) which normally reduces the concentration of ions present in an acid or a base to become more dilute.</u>

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Vitek1552 [10]

Answer:

The answer is

<h2>219.5 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 4500 g

density = 20.5 g/cm³

We have

volume =  \frac{4500 }{20.5}  \\  = 219.51219...

We have the final answer as

<h3>219.51 mL</h3>

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8 0
2 years ago
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KATRIN_1 [288]

Answer:

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Explanation:

8 0
2 years ago
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Likurg_2 [28]
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7 0
3 years ago
How many moles of Fluorine (F2) are<br><br> needed to completely react 8.0<br><br> moles of NF3?
Anna [14]

Answer:

12 moles of F₂

Explanation:

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From the balanced equation above,

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From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Therefore, Xmol of F₂ will react to produce 8 moles of NF₃ i.e

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8 0
2 years ago
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Mice21 [21]

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Hope this was Helpful

5 0
3 years ago
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