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timama [110]
3 years ago
14

Plzzzzzz help!! I will give brainliest to whoever answers

Mathematics
2 answers:
jarptica [38.1K]3 years ago
5 0

Answer:

4 and -3 i think

Step-by-step explanation:

the dot is on 4 and -3

11Alexandr11 [23.1K]3 years ago
3 0

Answer:

I think it is (4,-3)

Step-by-step explanation:

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An arithmetic sequence has a first term of 6.3 and a second term of 8.8 Which term has a value of 78.8?
slega [8]
First term [ a ] = 6.3

Common difference [ d ] = 8.8 - 6.3 = 2.5 

Using general term formula,

t_{n} = a + (n-1)d

78.8 = 6.3 + (n-1)*2.5

2.5*(n-1) = 72.5 [ Dividing both sides by 2.5 ]

n-1 = 29

n = 30

Hence, 78.8 is the 30th term in the arithmetic series.
4 0
3 years ago
5.) - 7(-2x - 9) = 133<br> how do you solve this
Ray Of Light [21]

Answer: x= 5

Step-by-step explanation: Distribute the -7 into the parentheses, we get 14x+63=133. You then minus 63 on the left side of the equation and on the right side of the equation. You will get 14x=70. You then solve x by dividing 70 by 14 you will get x=5.

4 0
3 years ago
1. Find the lengths of the missing sides in the pairs of s 5 X 4 2 3 7​
Ahat [919]

Answer:

21185

Step-by-step explanation:

7 0
2 years ago
The larger leg of a right triangle is 3cm longer than its smaller leg. The hypotenuse is 6cm longer than the smaller leg. how ma
Natalka [10]
b=a+3\\&#10;c=a+6\\&#10;a^2+b^2=c^2\\\\&#10;a^2+(a+3)^2=(a+6)^2\\&#10;a^2+a^2+6a+9=a^2+12a+36\\&#10;a^2-6a-27=0\\&#10;a^2-9a+3a-27=0\\&#10;a(a-9)+3(a-9)=0\\&#10;(a+3)(a-9)=0\\&#10;a=-3 \vee a=9\\&#10;

The length can't be negative, so the answer is 9 cm.

5 0
2 years ago
Read 2 more answers
Mallorie has $3 in her wallet. If this is 10% of her monthly allowance, what is her monthly allowance?
LiRa [457]
Ok so let me tell you how can this be done:
<span>The part she has is $3. The percent is 10%. So,
</span><span><span>3 /.10</span>= 30</span><span> 1/10 =  0.10
</span>This is true because of the formula
<span><span>part / </span><span>whole  </span></span>×100=percen<span>t
</span>Hope this is useful
4 0
3 years ago
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