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Xelga [282]
3 years ago
11

Chemistry salty defin​

Chemistry
1 answer:
Neko [114]3 years ago
7 0

Answer:

look it up on gogole and if that doesnt work try asking teachers or take notes in class

Explanation:

You might be interested in
Express the quantity 556.2 x 10^-12 in each units<br> A.) ms<br> B.) ns<br> C.) ps<br> D.) fs
zavuch27 [327]
The answer:
we should know the meaning of each abbreviation:
ms means  millisecond, its value is 10^-3 s 
ns means  means  nanosecond,   its value is 10^-9 s
ps means  picosecond, its value is 10^-12 s
fs means  femtosecond, its value is 1x 10^15 s

<span>Expressions of the quantity 556.2 x 10^-12 are</span>
556.2 x 10^-12 =556.2 ps
556.2 x 10^-12 =556.2 x 10^-9 x 10^-3= 556.2 x 10^-9 ms
556.2 x 10^-12 = 556.2 x 10^-3 x 10^-9 = 556.2 x 10^-3 ns
556.2 x 10^-12 = 556.2 x 10^- 27 x 10^15 = 556.2 x 10^- 27 fs
6 0
3 years ago
Why do we observe national day​
WITCHER [35]

A national day is a day on which celebrations mark the nationhood of a nation or state. It may be the date of independence, of becoming a republic, or a significant date for a patron saint or a ruler (such as a birthday, accession, or removal). The national day is often a public holiday.

5 0
3 years ago
How are stars and comets different?
ehidna [41]
The answer is letter C.

Because we classify something as a star when it is: a large ball of gas that undergoes nuclear fusion. Given this definition, a comet is not a star. A comet is a ball of ice and dirt hurtling through space, it shines only because it reflects ligh
3 0
2 years ago
PLEASE HELP
Olenka [21]
There is no reaction because of the common ion effect(which in this case is K)if there were a reaction the products would be the same as the reactants so no reaction happens
5 0
3 years ago
Determine how many millilitres of a 4.25 M HCl solution are needed to react completely with 8.75 g CaCO3?
Helen [10]

Answer:

41 mL

Explanation:

Given data:

Milliliter of HCl required = ?

Molarity of HCl solution = 4.25 M

Mass of CaCO₃ = 8.75 g

Solution:

Chemical equation:

2HCl + CaCO₃      →    CaCl₂ + CO₂ + H₂O

Number of moles of CaCO₃:

Number of moles = mass/molar mass

Number of moles = 8.75 g / 100.1 g/mol

Number of moles = 0.087 g /mol

Now we will compare the moles of  CaCO₃ with HCl.

                      CaCO₃         :          HCl

                          1               :            2

                      0.087           :         2/1×0.087 = 0.174 mol

Volume of HCl:

Molarity = number of moles / volume in L

4.25 M = 0.174 mol / volume in L

Volume in L = 0.174 mol /4.25 M

Volume in L = 0.041 L

Volume in mL:

0.041 L×1000 mL/ 1L

41 mL

8 0
3 years ago
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