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ExtremeBDS [4]
3 years ago
7

How does density affect the pressure of a liquid?Anyone plz answer​

Physics
1 answer:
eimsori [14]3 years ago
7 0

Answer:

As the density of the liquid increases, so does the pressure. If the liquid is open to the air, there will also be atmospheric pressure on its surface.

Explanation:

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Which pair of quantities represents scalar quantities
____ [38]

Answer:

physical quantity that only has magnitude and no other characteristics.

Explanation:

so no velocity only magnitude

6 0
3 years ago
Describe how the boiling point of water on top of a mountain would be different from its boiling point at sea level.
Sonbull [250]

Answer:

At elevated altitudes, any cooking that involves boiling or steaming generally requires compensation for lower temperatures because the boiling point of water is lower at higher altitudes due to the decreased atmospheric pressure.

Explanation:

7 0
3 years ago
What is the formula to calculate the GPE of an object?
Bas_tet [7]

Answer:

mass x gravity x height

Explanation:

Gravitational potential energy is measured in jules

3 0
3 years ago
Read 2 more answers
The cornea behaves as a thin lens of focal lengthapproximately 1.80 {\rm cm}, although this varies a bit. The material of whichi
Keith_Richards [23]

Answer:

Explanation:

  a )

from lens makers formula

\frac{1}{f} =(\mu-1)(\frac{1}{r_1} -\frac{1}{r_2})

f is focal length , r₁ is radius of curvature of one face and r₂ is radius of curvature of second face

putting the values

\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})

1.462 = 2 - 1 / r₂

1 / r₂ = .538

r₂ = 1.86 cm .

= 18.6 mm .

b )

object distance u = 25 cm

focal length of convex lens  f  = 1.8 cm

image distance  v   = ?

lens formula

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}

\frac{1}{v} = \frac{1}{1.8} -\frac{1}{25}

.5555 - .04

= .515

v = 1.94 cm

c )

magnification = v / u

= 1.94 / 25

= .0776

size of image = .0776 x size of object

= .0776 x 10 mm

= .776 mm

It will be a real image and it will be inverted.

 

5 0
3 years ago
Calculate the magnitude of the average gravitational force between earth and the moon
zepelin [54]
F = G mM / r^2, where 
<span>F = gravitational force between the earth and the moon, </span>
<span>G = Universal gravitational constant = 6.67 x 10^(-11) Nm^2/(kg)^2, </span>
<span>m = mass of the moon = 7.36 × 10^(22) kg </span>
<span>M = mass of the earth = 5.9742 × 10^(24) and </span>
<span>r = distance between the earth and the moon = 384,402 km </span>

<span>F </span>
<span>= 6.67 x 10^(-11) * (7.36 × 10^(22) * 5.9742 × 10^(24) / (384,402 )^2 </span>
<span>= 1.985 x 10^(26) N</span>
5 0
3 years ago
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