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AleksAgata [21]
3 years ago
15

The Earth rotates on its axis every __________ and revolves around the Sun every __________.

Physics
2 answers:
Ray Of Light [21]3 years ago
9 0
The earth rotates on its axis every DAY and revolves around the Sun every YEAR.
kvasek [131]3 years ago
7 0
Earth rotates about this axis once each day (approximately 24 hours)
and revolves around the sun every year ..
Hope this helped ! :)
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stiv31 [10]

Answer: .

Explanation:

3 0
3 years ago
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What is the moment of inertia of an object that rolls without slipping down a 3.5-m- high incline starting from rest, and has a
Daniel [21]

Answer:

I = 0.287 MR²

Explanation:

given,

height of the object = 3.5 m

initial velocity = 0 m/s

final velocity  = 7.3 m/s

moment of inertia = ?

Using total conservation of mechanical energy

change in potential energy will be equal to change in KE (rotational) and KE(transnational)

PE = KE(transnational) + KE (rotational)

mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}I\omega^2

v = r ω

mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}\dfrac{Iv^2}{r^2}

I = \dfrac{m(2gh - v^2)r^2}{v^2}

I = \dfrac{mr^2(2\times 9.8 \times 3.5 - 7.3^2)}{7.3^2}

I =mr^2(0.287)

I = 0.287 MR²

3 0
3 years ago
What is conservation of energy in physics?
horsena [70]

Answer:

https://www.khanacademy.org/science/physics/work-and-energy/work-and-energy-tutorial/a/what-is-conservation-of-energy

Explanation:

Look at this website it gives you all the details! :)

7 0
3 years ago
A 4 kg block is pulled with 5.6 N of force to the right. The block experiences 1.1 N of friction. What is the acceleration of th
BARSIC [14]

Answer:

The acceleration of the box is 1.125 m/s² towards right.

Explanation:

Mass of the box, m=4 kg

Force acting towards right, F=5.6 N

Frictional force acting towards left, f=1.1 N

Let the acceleration be a m/s².

Now, net force acting on the box towards right is given as:

F_{net}=F-f=5.6-1.1=4.5\textrm{ N}

From Newton's second law of motion,

F_{net}=ma\\4.5=4a\\a=\frac{4.5}{4}=1.125\textrm{ }m/s^2

Therefore, the acceleration of the box is 1.125 m/s² towards right.

7 0
4 years ago
The block accelerates down the 30 degree incline at 3m/s2. What is the coefficient of friction of these surfaces
dolphi86 [110]
Fnet = Fg sin 30 - Ff
ma = mg sin 30 - mew Fg cos 30
ma = mg sin 30 - mew mg cos 30
a = g sin 30 - mew gcos30
a - g sin 30 = - mew g cos 30
mew = -(a - g sin30)/(g cos 30)
mew = -(3m/s2 - 9.81sin30)/(9.81 cos 30)
mew = 0.22
8 0
3 years ago
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