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Pepsi [2]
3 years ago
14

A truck with 34-in.-diameter wheels is traveling at 55 mi/h. Find the angular speed of the wheels in rad/min, *hint convert mile

s to inches & hours to minutes:
Physics
1 answer:
julia-pushkina [17]3 years ago
7 0

Answer:

w =3416 rad/min  

Explanation:

The angular speed of the wheels in radians can be defined as follows:

w=\frac{s}{r}

where

w = angular speed

r = radius of the wheel

s =distance traveled per minute

in this case we have

r = 34/2 inches = 17 inches

s = (55 mi/hr) (5280 ft/mi) (12 in/ft) (1hr/60min) = 58,080 inches/min

Therefore, w = 58,080/ 17 = 3416 rad/min  

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uysha [10]

Answer:

Explanation:

1. Frictional force is responsible for running of car and buses on roads.

2.Gravitational force exists between astronauts in space.

3. Magnetic for is responsible to attract the iron objects using a magnet

4.Electrostatic force is responsible for fiber to stick on the skin.This force occurs due to the presence of charge.

5.When a person is pushing a trolley then object experience a normal reaction from ground.

6.Gravitational force makes the planet to move in their orbits.

4 0
3 years ago
To qualify to run in the 2005 Boston Marathon, a distance of 26.2 miles, an 18-year-old woman had to have completed another mara
Korvikt [17]

Answer:

7,14545 mph and 3,1936 m/s

Explanation:

The average speed is calculated by dividing the displacement over time, then it is 26,2 miles/(3 2/3 hours), here 3 (2/3) hours is a mixed number, that represents 11/3 hours or 3,66 hours. Then the average speed is 7,14545 mph, now to turn this into meters per second, we notice as mentioned that 1 mile =1609 meters and 1 hour=3600 seconds. Then 7,14545 miles/hour* (1 hour/3600 seconds) * (1609 meters/1 mile)=3,1936 m/s

3 0
2 years ago
Which pair of quantities includes one quantity that increases as the other decreases during simple harmonic motion?
11111nata11111 [884]

Kinetic energy and potential energy pair is the quantity in which one will increase then other will decrease

As we know that sum of kinetic energy and potential energy will always remain conserved

So here we will have

KE + PE = constant

so here as we move away from mean position the kinetic energy will decrease while at the same time potential energy will increase.

So the pair of potential energy and kinetic energy will satisfy the above condition

7 0
3 years ago
Read 2 more answers
How to find the total displacement of an object ?
OLga [1]

Answer:

it can be calculated by measuring the final distance away from a point, and then subtracting the initial distance

8 0
3 years ago
A glass flask whose volume is 1000 cm^3 at a temperature of 1.00°C is completely filled with mercury at the same temperature. W
Marat540 [252]

Answer:

the coefficient of volume expansion of the glass is \mathbf{  ( \beta_{glass} )= 1.333 *10^{-5} / K}

Explanation:

Given that:

Initial volume of the glass flask = 1000 cm³ = 10⁻³ m³

temperature of the glass flask and mercury= 1.00° C

After heat is applied ; the final temperature = 52.00° C

Temperature change ΔT = 52.00° C - 1.00° C = 51.00° C

Volume of the mercury overflow = 8.50 cm^3 = 8.50 ×  10⁻⁶ m³

the coefficient of volume expansion of mercury is 1.80 × 10⁻⁴ / K

The increase in the volume of the mercury =  10⁻³ m³ ×  51.00 × 1.80 × 10⁻⁴

The increase in the volume of the mercury = 9.18*10^{-6} \ m^3

Increase in volume of the glass =  10⁻³ × 51.00 × \beta _{glass}

Now; the mercury overflow = Increase in volume of the mercury - increase in the volume of the flask

the mercury overflow = (9.18*10^{-6}  -  51.00* \beta_{glass}*10^{-3})\ m^3

8.50*10^{-6} = (9.18*10^{-6}  -51.00* \beta_{glass}* 10^{-3} )\ m^3

8.50*10^{-6} - 9.18*10^{-6} = ( -51.00* \beta_{glass}* 10^{-3} )\ m^3

-6.8*10^{-7} =  ( -51.00* \beta_{glass}* 10^{-3} )\ m^3

6.8*10^{-7} =  ( 51.00* \beta_{glass}* 10^{-3} )\ m^3

\dfrac{6.8*10^{-7}}{51.00 * 10^{-3}}=  ( \beta_{glass} )

\mathbf{  ( \beta_{glass} )= 1.333 *10^{-5} / K}

Thus; the coefficient of volume expansion of the glass is \mathbf{  ( \beta_{glass} )= 1.333 *10^{-5} / K}

5 0
2 years ago
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