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Pepsi [2]
3 years ago
14

A truck with 34-in.-diameter wheels is traveling at 55 mi/h. Find the angular speed of the wheels in rad/min, *hint convert mile

s to inches & hours to minutes:
Physics
1 answer:
julia-pushkina [17]3 years ago
7 0

Answer:

w =3416 rad/min  

Explanation:

The angular speed of the wheels in radians can be defined as follows:

w=\frac{s}{r}

where

w = angular speed

r = radius of the wheel

s =distance traveled per minute

in this case we have

r = 34/2 inches = 17 inches

s = (55 mi/hr) (5280 ft/mi) (12 in/ft) (1hr/60min) = 58,080 inches/min

Therefore, w = 58,080/ 17 = 3416 rad/min  

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g How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for
lbvjy [14]

Answer:

2

Explanation:

We know that in the Fraunhofer single-slit pattern,

maxima is given by

a\text{sin}\theta=\frac{2N+1}{2}\lambda

Given values

θ=2.12°

slit width a= 0.110 mm.

wavelength λ= 582 nm

Now plugging values to calculate N we get

0.110\times10^{-3}\text{sin}2.12=(\frac{2N+1}{2})582\times10^{-9}

Solving the above equation we get

we N= 2.313≅ 2

4 0
3 years ago
Earning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement
lana [24]

Answer:

the work done by the 30N force is 4156.92 J.

For this problem, they don´t ask you to determine the work of the total force applied in the block. They only want the work done for the force of 30N, with an angle of 30º respectively of the displacement and a traveled distance of 160m. So:

W=F·s·cos(α)=30N·160m·cos(30º)=4156.92J

8 0
2 years ago
an electric current 0.75 a passes through a circuit that has a resistance of 175. according to ohm's law, what is the voltage of
Aleksandr [31]

Answer:

131.25

Explanation:

i worked it out on a diffrent sheet so its hard to explain

8 0
2 years ago
A bee wants to fly to a flower located due North of the hive on a windy day. The wind blows from East to West at speed 6.68 m/s.
Aleonysh [2.5K]

Answer:  53.31\° East of North

Explanation:

We have the following data:

Speed of the wind from East to West: 6.68 m/s

Speed of the bee relative to the air:  8.33 m/s

If we graph these speeds (which in fact are velocities because are vectors) in a vector diagram, we will have a right triangle in which the airspeed of the bee (its speed relative to te air) is the hypotense and the two sides of the triangle will be the <u>Speed of the wind from East to West</u> (in the horintal part) and the <u>speed due North relative to the ground</u> (in the vertical part).

Now, we need to find the direction the bee should fly directly to the flower (due North):

sin \theta=\frac{Windspeed-from-East-to-West}{Speed-bee-relative-to-air}

sin \theta=\frac{6.68 m/s}{8.33 m/s}

Clearing \theta:

\theta=sin^{-1} (\frac{6.68 m/s}{8.33 m/s})

\theta=53.31\°

6 0
3 years ago
For the following elementary reaction 2br• -&gt; br2-. The rate of consumption of the reaction and the rate of formation of prod
Scorpion4ik [409]

Answer: -\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

2Br^.\rightarrow Br_2

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{d[Br^.]}{2dt}

or Rate=+\frac{d[Br_2]}{dt}

Thus -\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}

4 0
3 years ago
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