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Ganezh [65]
2 years ago
11

What science govern in nanostructure?​

Chemistry
2 answers:
son4ous [18]2 years ago
5 0
<h3>{\tt{\red{\underline{\underline{\huge{Question:}}}}}}</h3>

<h3>What science govern in nanostructure?</h3>

<h3>{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}</h3>

\longrightarrow The materials having dimensions between 1 and 100 nanometeres are called nonostructures and the science that operates at nano scale is called Nanotechnology.

\huge\boxed{\fcolorbox{blue}{red}{Thank \: you}}

Mademuasel [1]2 years ago
5 0
Bbtvtvtvt your bdybb Co junk
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An aqueous salt solution is 15.0% mass sodium chloride. How many grams of salt are in 250.0 grams of this solution? Use correct
Shtirlitz [24]

Answer:

37.5 g NaCl

Explanation:

Step 1: Given data

  • Concentration of NaCl: 15.0% m/m
  • Mass of the solution: 250.0 g

Step 2: Calculate how many grams of NaCl are in 250.0 g of solution

The concentration of NaCl is 15.0% by mass, that is, there are 15.0 g of NaCl every 100 g of solution.

250.0 g Solution × 15.0 g NaCl/100 g Solution = 37.5 g NaCl

5 0
3 years ago
Carbonated drinks in cans have a small amount of space above the liquid level inside the can known as the “headspace.” What woul
andrey2020 [161]
The temperature will stay constant.
3 0
3 years ago
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Are the atoms really "sharing" electrons? Explain.
Iteru [2.4K]

Answer:

yes, in certain cases

there are different types of bondings between atoms

and in some they lend electrons to make their atom stable this type of bonding is called ionic bonding

and in covalent bond the atoms share their electrons

7 0
3 years ago
A certain liquid X has a normal boiling point of 108.30 °C and a boiling point elevation constant Kb=1.07 °C kg/mol. A solution
Fynjy0 [20]

Answer:

34,6g of (NH₄)₂SO₄

Explanation:

The boiling-point elevation describes the phenomenon in which the boiling point of a liquid increases with the addition of a compound. The formula is:

ΔT = kb×m

Where ΔT is Tsolution - T solvent; kb is ebullioscopic constant and m is molality of ions in solution.

For the problem:

ΔT = 109,7°C-108,3°C = 1,4°C

kb = 1.07 °C kg/mol

Solving:

m = 1,31 mol/kg

As mass of X = 600g = 0,600kg:

1,31mol/kg×0,600kg = 0,785 moles of ions. As (NH₄)₂SO₄ has three ions:

0,785 moles of ions×\frac{1(NH_{4})_{2}SO_{4}}{3Ions} = 0,262 moles of (NH₄)₂SO₄

As molar mass of (NH₄)₂SO₄ is 132,14g/mol:

0,262 moles of (NH₄)₂SO₄×\frac{132,14g}{1mol} = <em>34,6g of (NH₄)₂SO₄</em>

<em></em>

I hope it helps!

7 0
3 years ago
Allen is carrying out reactions in a lab. One of the products in all reactions is found to be either a precipitate, a gas, or wa
vampirchik [111]
Here are some examples for those type of reactions.
<span>
Combustion reaction: CH4(g) + 2 O2(g) --> CO2(g) + 2 H2O(l)
</span><span>
Decomposition reaction: CaCO3(s) ---> CaO(s) + CO2(g)

</span><span>Double replacement: AgNO3(aq) + NaCl(aq) ---> AgCl(s) + NaNO3(aq)


</span>One common thing in all is that they are reactions. They have reactants to form new substances called product.
4 0
2 years ago
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