1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
son4ous [18]
3 years ago
15

An unknown solution has a pH of 8. How would you classify the solution? A.acidic B.basic C.neutral D.There is not enough informa

tion to answer the question
Chemistry
2 answers:
eimsori [14]3 years ago
6 0
<h2>Answer:</h2>

The correct answer is A. The solution is acidic in nature.

<h3>Explanation:</h3>

According to standard PH scale ranges;

  • <u>Solution is neutral, when PH is 7.</u>
  • <u>Solution is basic if PH is less than 7.</u>
  • <u>Solution is acidic if PH of solution is more than 7.</u>

So in this solution PH of solution is 8. According to standard criteria unknown solution is acidic in nature.

Alex_Xolod [135]3 years ago
4 0

pretty sure its c 95% sure

You might be interested in
How does beta decay affect the atomic number?
MA_775_DIABLO [31]
The atomic mass number does<span> not change because a </span>beta<span> particle has a much smaller </span>mass<span> than the </span>atom<span>. The </span>atomic number<span> goes up because a neutron has turned into an extra proton. </span>Beta decay<span> is fundamentally different from alpha </span>decay<span>. An alpha particle is made of two protons and two neutrons.</span>
6 0
3 years ago
Question 2
san4es73 [151]

Explanation:

its hard to explain unless we know what the question fully asks..

4 0
2 years ago
If a reaction has an equilibrium constant slightly greater than 1, what type of reaction is it?
Paha777 [63]
Reversible, flavoring products
4 0
3 years ago
Read 2 more answers
You need to prepare a solution with a specific concentration of Na+Na+ ions; however, someone used the end of the stock solution
babymother [125]

Explanation:

Ionic equation

NaCl(aq) --> Na+(aq) + Cl-(aq)

Na2SO4(aq) --> 2Na+(aq) + SO4^2-(aq)

In NaCl solution, 1 mole of Na+ is dissociated in 1 liter of solution while in Na2SO4, 2 moles of Na+ is dissociated in 1 liter of solution.

Molecular weight of NA2SO4 = (23*2) + 32 + (16*4)

= 142 g/mol

Molecular weight of NaCl = 23 + 35.5

= 58.5 g/mol

Masses

% Mass of NA+ in Na2SO4 = mass of Na+/total mass of Na2SO4 * 100

= 46/142 * 100

= 32.4%

% Mass of NA+ in NaCl = mass of Na+/total mass of NaCl * 100

= 23/58.5 * 100

= 39.3%

Therefore, the % mass of Na+ in NaCl and Na2SO4 are different so it cannot be used.

7 0
3 years ago
9.44 x 10^3 In standard form
Marta_Voda [28]
9440 is standard form.
5 0
3 years ago
Other questions:
  • What is another name for the activation energy barrier in a reaction?
    9·2 answers
  • A large marble is dropped in a graduate cylinder with 35ml of water in it .The water level increases to 49ml.what is the volume
    12·2 answers
  • is it true that in a solution the tiny pieces of one substance are spread equally through the other substance
    12·1 answer
  • Carbon-14 (14C) dating assumes that the carbon dioxide on the Earth today has the same radioactive content as it did centuries a
    15·1 answer
  • What distinguishes effusion from diffision? How are these processes similar?
    8·1 answer
  • What is the change of state from gas to liquid
    11·1 answer
  • Which stroke is this describing?
    8·2 answers
  • What is a tornado and how does it form? ( Don't search the answer )
    6·2 answers
  • A rock is an example
    9·1 answer
  • PC13 ionic or covalent
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!