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denpristay [2]
3 years ago
12

How do i do this question please help me

Chemistry
1 answer:
postnew [5]3 years ago
7 0

Answer:

3

Explanation:

The reaction is given as:

           H₂S   +   O₂   →  SO₂    +    H₂O

Let us balance the chemical equation.

 We take some letters and we use them as the coefficient to balance the equation;

          aH₂S   +   bO₂   →  cSO₂    +    dH₂O

Now,

  Conserving H;

         2a  = 2d

 Conserving S;

         a = c

 Conserving O;

        2b  = 2c + d  

Let a  = 1, d  = 1, c  = 1, b  = \frac{3}{2}  and multiply through by 2;

    a = 2, b  = 3, c  = 2 and d = 2

So, the balanced reaction equation is given as;

    2H₂S   +   3O₂   →  2SO₂    +    2H₂O

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Explanation:

¡Hola!

En este caso, dada la información para estos problemas, procedemos de la siguiente manera, basado en las leyes de los gases ideales:

1. Una masa de aire ocupa un volumen de 5 litros a una temperatura de 120 °C Cual será el nuevo volumen si la temperatura se reduce a la mitad:

Aqui, utilizamos la ley de Charles, asegurándonos que la temperatura está en Kelvin:

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2. Un gas ideal ocupa un volumen de 4000 ml a una presión absoluta de 1500 kilo pascal Cual será la presión si el gas es comprimido lentamente hasta 750 kilo pascal a temperatura constante?

Aquí, utilizamos la ley de Boyle, dado que la temperatura se mantiene constante, calculando el volumen, ya que lo que se da es la presión final:

\neq P_2V_2=P_1V_1\\\\V_2=\frac{P_1V_1}{P_2}\\\\ V_2=\frac{4000mL*1500kPa}{750kPa}\\\\V_2=8000mL

3. Un gas ocupa un volumen de 200 litros a 95°C y 782 mmHg Cual será el volumen ocupado por dicho gas a 65°C y 815 mmHg:

Aquí, utilizamos la ley combinada de los gases ideales, asegurándonos que las temperaturas están en Kelvin:

\frac{T_2}{P_2V_2} =\frac{T_1}{P_1V_1} \\\\V_2 =\frac{P_1V_1T_2}{P_2T_1} \\\\V_2 =\frac{782mmHg*200L*338K}{815mmHg*368K}\\\\V_2=176.3L

¡Saludos!

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