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Elis [28]
3 years ago
10

Zinc chloride can be made from the reaction between zinc oxide and hydrochloric acid. Describe a laboratory method to produce pu

re dry  crystals of zinc chloride. (6 marks)

Suggest an alternative to zinc oxide that could react with hydrochloric acid to give you the desirable product.(1 mark)
Chemistry
1 answer:
VikaD [51]3 years ago
7 0

Answer:

answer: Pure dry crystals of zinc chloride can be produced by crystallisation, then filtration to remove excess solution, followed by drying on a watch glass or in a warm oven.

answer- Yes. The reaction of hydrochloric acid with zinc oxide to form zinc chloride and water is a neutralization reaction because acid (HCl) is a neutralizing base (ZnO).

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Why methylated spirits burn?​
pishuonlain [190]

Answer:

Methylated \:  spirits \:  are \:   \: extremely \:  flammable.

Explanation:

Incorrect use has resulted in accidents and disfiguring burns. Never leave a methylated spirit appliance unattended. Also make sure that the camping stove or appliance is on a flat surface and that the fuel cannot spill out.

5 0
2 years ago
What does Avogadro's law state and what is the formula​
sertanlavr [38]

The law is approximately valid for real gases at sufficiently low pressures and high temperatures. The specific number of molecules in one gram-mole of a substance, defined as the molecular weight in grams, is 6.02214076 × 1023, a quantity called Avogadro's number, or the Avogadro constant.

5 0
2 years ago
Read 2 more answers
Calculate the solubility of zn(oh)2(s) in 2.0 m naoh solution. (hint: you must take into account the formation of zn(oh)2−4, whi
Brilliant_brown [7]
When we have:

Zn(OH)2 → Zn2+ 2OH-  with Ksp = 3 x 10 ^-16

and:

Zn2+ + 4OH- → Zn(OH)4 2-  with Kf = 2 x 10^15
 
by mixing those equations together:

Zn(OH)2 + 2OH- → Zn(OH)4 2- with K = Kf *Ksp = 3 x 10^-16 * 2x10^15 =0.6

by using ICE table:

         Zn(OH)2 + 2OH- → Zn(OH)4 2-

initial                     2m              0

change                  -2X                +X     

Equ                       2-2X                 X

when we assume that the solubility is X

and when K = [Zn(OH)4 2-] / [OH-]^2

        0.6 = X / (2-2X)^2    by solving this equation for X

∴ X = 0.53 m

∴ the solubility of Zn(OH)2 = 0.53 M
4 0
3 years ago
If a horse is at a stop and the. Starts running is the horse accelerating or decelerating?
Feliz [49]
Accelerating, because it’s going from standing still to running, so the speed increases
5 0
3 years ago
Read 2 more answers
A first-order reaction is 45% complete at the end of 43 minutes. What is the length of the half-life of this reaction
shtirl [24]

The half-life of the reaction is 50 minutes

Data;

  • Time = 43 minutes
  • Type of reaction = first order
  • Amount of Completion = 45%

<h3>Reaction Constant</h3>

Let the initial concentration of the reaction be X_0

The reactant left = (1 - 0.45) X_0 = 0.55 X_0 = X

For a first order reaction

\ln(\frac{x}{x_o}) = -kt\\ k = \frac{1}{t}\ln (\frac{x_o}{x}) \\ k = \frac{1}{43}\ln (\frac{x_o}{0.55_o})\\ k = 0.013903 min^-^1

<h3>Half Life </h3>

The half-life of a reaction is said to be the time required for the initial amount of the reactant to reach half it's original size.

x = \frac{x_o}{2} \\t = t_\frac{1}{2} \\t_\frac{1}{2} = \frac{1}{k}\ln(\frac{x_o}{x_o/2})\\

Substitute the values

t_\frac{1}{2} = \frac{1}{k}\ln(2)=\frac{0.6931}{0.013903}\\t_\frac{1}{2}= 49.85 min = 50 min

The half-life of the reaction is 50 minutes

Learn more on half-life of a first order reaction here;

brainly.com/question/14936355

4 0
2 years ago
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