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drek231 [11]
3 years ago
5

What are the main postulates of Bohr's model?

Chemistry
1 answer:
MakcuM [25]3 years ago
8 0

Answer:

1. In an atom, electrons (negatively charged) revolve around the positively charged nucleus in a definite circular path called as orbits or shells.

2. Each orbit or shell has a fixed energy and these circular orbits are known as orbital shells.

3. The energy levels are represented by an integer (n=1, 2, 3…) known as the quantum number. This range of quantum number starts from nucleus side with n=1 having the lowest energy level. The orbits n=1, 2, 3, 4… are assigned as K, L, M, N…. shells and when an electron attains the lowest energy level it is said to be in the ground state.

4. The electrons in an atom move from a lower energy level to a higher energy level by gaining the required energy and an electron moves from a higher energy level to lower energy level by losing energy.

Explanation:

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Which compound is an Arrhenius base?
Dmitry_Shevchenko [17]
I was hoping that some choices would be given to choose from. As there are no choices given, so i am answering the question based on my knowledge and hope that it comes to your help. Calcium hydroxide is a good example of Arrhenius base. An Arrhenius base is actually a substance that releases a hydroxyl ion in water.
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Within a group, does the radii of atoms increase or decrease as the atomic
EleoNora [17]

Answer:increase

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If someone is suffering from the problem of acidity after overeating, which of the following would you suggest as remedy ?
kolezko [41]

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nth

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6 0
3 years ago
Determine the freezing point of a 0.51 molal
Elan Coil [88]

Answer:

-65.897°C.

Explanation:

  • Adding solute to water causes depression of the boiling point.
  • The depression in freezing point (ΔTf) can be calculated using the relation: <em>ΔTf = Kf.m,</em>

where, ΔTf is the depression in freezing point of chloroform solution.

Kf is the molal depression constant of chloroform (Kf = 4.70°C.kg/mol).

m is the molality of the solution (m = 0.51 m).

∴ ΔTf = Kf.m = (4.70°C.kg/mol)(0.51 m) = 2.397°C.

∴ The freezing point of the solution = (freezing point of chloroform) - ΔTf = (-63.5°C) - (2.397°C) = -65.897°C.

7 0
3 years ago
Suppose you have 15.0 ml of zinc. What volume of aluminum would have the same mass as the zinc?
Black_prince [1.1K]

Answer:

\large \boxed{\text{41.2 cm}^{3}}

Explanation:

1. Mass of zinc

The density of zinc is 7.14 g/cm³

D = m/V

\begin{array}{rcl}7.14 & = & \dfrac{m}{15.0}\\\\m & = & 7.14 \times 15.0\\& = & \text{107.1 g}\\\end{array}\\

2. Volume of aluminium

The density of aluminium is 2.60/cm³.

\begin{array}{rcl}2.60 & = & \dfrac{107.1}{V}\\\\2.60V & = & 107.1\\V& = &\dfrac{107.1}{2.60}\\\\& = &\textbf{41.2cm}^{\mathbf{3}}\\\end{array}\\\large \boxed{\textbf{41.2 cm}^{\mathbf{3}}}\text{ of aluminium have the same mass as 15.0 cm$^{3}$ of zinc.}

5 0
3 years ago
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