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Sonja [21]
2 years ago
6

The volume of water in a graduated cylinder was increased from 52.0 mL to 75.5 mL when a piece of irregular metal was placed in

the water. If the piece of metal has a mass of 265.6 g, what is the density of the metal?
Chemistry
2 answers:
Artyom0805 [142]2 years ago
6 0

Answer:

<h2>11.30 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

volume = final volume of water - initial volume of water

volume = 75.5 - 52 = 23.5

From the question we have

density =  \frac{265.6}{23.5}  \\  = 11.302127...

We have the final answer as

<h3>11.30 g/mL</h3>

Hope this helps you

olga nikolaevna [1]2 years ago
5 0

Answer:

Approximately 11.3 g/mL

Explanation:

The formula for density is mass divided by density. In this problem, the mass is already given: 265.6 grams. The density is the part with the milliliters. 75.5 mL - 52.0 mL is 23.5 mL.

After plugging these numbers into the formula, you get 265.6 g/23.5 mL. After divided those numbers, you get 11.30212..... g/mL, which rounds to 11.30 g/mL.

I hope this helps!

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Balanced chemical equation:

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Step 1:

2C₂H₆ +  O₂     →      CO₂ + H₂O

Left hand side                      Right hand side

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H = 12                                    H = 2

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Step 2:

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Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 2

O = 2                                     O = 9

Step 3:

2C₂H₆ +  O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 2                                     O = 14

Step 4:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 14                                     O = 14

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