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Sonja [21]
3 years ago
6

The volume of water in a graduated cylinder was increased from 52.0 mL to 75.5 mL when a piece of irregular metal was placed in

the water. If the piece of metal has a mass of 265.6 g, what is the density of the metal?
Chemistry
2 answers:
Artyom0805 [142]3 years ago
6 0

Answer:

<h2>11.30 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

volume = final volume of water - initial volume of water

volume = 75.5 - 52 = 23.5

From the question we have

density =  \frac{265.6}{23.5}  \\  = 11.302127...

We have the final answer as

<h3>11.30 g/mL</h3>

Hope this helps you

olga nikolaevna [1]3 years ago
5 0

Answer:

Approximately 11.3 g/mL

Explanation:

The formula for density is mass divided by density. In this problem, the mass is already given: 265.6 grams. The density is the part with the milliliters. 75.5 mL - 52.0 mL is 23.5 mL.

After plugging these numbers into the formula, you get 265.6 g/23.5 mL. After divided those numbers, you get 11.30212..... g/mL, which rounds to 11.30 g/mL.

I hope this helps!

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Hello.

In this case, given the chemical reaction, we can compute the grams of oxygen by using the 98.2 g of water via the 2:1 mole ratio between them, the molar mass of water that is 18.02 g/mol, the molar mass of gaseous oxygen that is 32.00 g/mol and the following stoichiometric procedure relating the given information:

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