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arsen [322]
3 years ago
15

A student walks 50 m north, stops, and then travels 32 m south. What is her displacement?

Chemistry
1 answer:
goblinko [34]3 years ago
7 0

Her displacement = 18 m

<h3>Further explanation</h3>

Given

walks 50 m north and 32 m south

Required

displacement

Solution

Displacement shows vector motion that has magnitude and direction.

Displacement only looks at the distance between the starting point and the end point

Because it takes direction into account, a positive or negative sign is required

We determine that in vertical motion the upward direction is positive and the downward direction is negative

While the horizontal movement to the right is positive and the left has a negative sign

Students moving north (from the starting point) are moving positively by + 50 m

then moving south which means moving negative as far as -32 m

So that the displacement is

\tt 50-32=18~m

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What is Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium
hram777 [196]

The Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium concentrations are Keq = 1.5. The correct option is D.

<h3>What is Keq?</h3>

Keq is the ratio of the concentration of reactant to the concentration of the product.

The balanced equation is

N₂ + 3H₂  = 2NH₃

The equilibrium constant is \rm \dfrac{[NH_3]^2}{[N_2]\; [H_2]^3}

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Thus, the correct option is D. Keq = 1.5.

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3 0
2 years ago
Natural gas is stored in a spherical tank at a temperature of 13°C. At a given initial time, the pressure in the tank is 117 kPa
drek231 [11]

Answer:

1.  the absolute pressure in the tank before filling = 217 kPa

2. the absolute pressure in the tank after filling = 312 kPa

3. the ratio of the mass after filling M2 to that before filling M1 = 1.44

The correct relation is option c (\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} })

Explanation:

To find  -

1. What is the absolute pressure in the tank before filling?

2. What is the absolute pressure in the tank after filling?

3. What is the ratio of the mass after filling M2 to that before filling M1 for this situation?

As we know that ,

Absolute pressure = Atmospheric pressure + Gage pressure

So,

Before filling the tank :

Given - Atmospheric pressure = 100 kPa ,  Gage pressure = 117 kPa

⇒Absolute pressure ( p1 )  = 100 + 117 = 217 kPa

Now,

After filling the tank :

Given - Atmospheric pressure = 100 kPa ,  Gage pressure = 212 kPa

⇒Absolute pressure (p2)  = 100 + 212= 312 kPa

Now,

As given, volume is the same before and after filling,

i.e. V_{1} = V_{2}

As we know that, P ∝ M

⇒ \frac{p_{1} }{p_{2} } = \frac{m_{1} }{m_{2} }

⇒\frac{m_{2} }{m_{1} } = \frac{p_{2} }{p_{1} }

⇒\frac{m_{2} }{m_{1} } = \frac{312 }{217 } = 1.4378 ≈ 1.44

Now, as we know that PV = nRT

As V is constant

⇒ P ∝ MT

⇒\frac{P}{T} ∝ M

⇒\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} }

So, The correct relation is c option.

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Because as the light left the galaxy, more of the light has been stretched and so more redshifted the light is.

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