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Irina18 [472]
3 years ago
13

a police car drives with a constant speed of 24 miles per hour .how long will it take to travela distance of 72 miles​

Physics
1 answer:
leonid [27]3 years ago
6 0

This problem is an exact copy of the other one that I just answered for you, about Grace driving 224 miles.  

Only the numbers are different, but the way to solve it is exactly the same.

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How much protein would be consumed with a 3-ounce serving of
dalvyx [7]

Answer:

15kg

(i actually did this)

Explanation:

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6 0
3 years ago
If mr galans paces is equal to 1.8 m,how many paces would it take to get to the moon
Anettt [7]

Answer:

The number of paces it would take to get to the Moon is 213,555,556 paces

Explanation:

The given length of Mr Galan's paces = 1.8 m/pace

The distance from the Earth to the Moon is, 384,400 km = 384,400,000 m

Therefore, the number of paces, "n", it would take to get to the Moon from the Earth is given as follows;

n = (The distance from the Earth to the Moon)/(The length of each Mr Galan's paces)

∴ n = 384,400,000 m/(1.8 m/pace) = 213,555,556 paces

The number of paces it would take to get to the Moon = n = 213,555,556 paces

5 0
3 years ago
A bag is dropped from a hovering helicopter. The bag has fallen for 7.2 s. How far has the bag fallen?
horrorfan [7]

Answer:

254 meters (when rounded), assuming you don't count the updraft of the blades, possible wind, and air resistance.  

Explanation:

Acceleration of gravity: 9.8 meters per second squared

Bag velocity: 70.56

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3 0
4 years ago
4. With respect to a mass of 1kg. (a) How much change in elevation must it undergo to change its potential energy by 1 kJ? (g=9.
mojhsa [17]

Answer:

102 m upwards.

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Just from a qualitative analysis we can tell the mass it needs to go upwards. How much we determine with the fact that the increase will be - in absolute value - equal to the work gravity does on it to go down that same distance.

Fixed that work being 1 kJ, we get

\vec F \cdot \vec{ \Delta h} = |F| |\Delta h| cos 0 = ( 9.8 N )\Delta h \cdot 1 = 10^3 J\\\Delta h = \frac {10^3}{9,8} m \approx 102 m

4 0
2 years ago
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Mujhe nhi pata sorry. Lekin mai bhut logo ko jaanti hoon jo iss savaal ka jawaab de sakte hai.

8 0
3 years ago
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