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Irina18 [472]
2 years ago
13

a police car drives with a constant speed of 24 miles per hour .how long will it take to travela distance of 72 miles​

Physics
1 answer:
leonid [27]2 years ago
6 0

This problem is an exact copy of the other one that I just answered for you, about Grace driving 224 miles.  

Only the numbers are different, but the way to solve it is exactly the same.

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the pull of gravity on mars is 3.7m/s^2. if a astronaut on mars lifts a 10 kg rock 1 m off the ground, just to see whats under i
Elanso [62]
Gravitational potential energy can be calculated using the formula:

PE_{grav} =mgh

Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height

On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.

So put in what you know and solve for what you don't know. 
m = 10kg
g = 3.7m/s^2
h = 1m

So we put that in and solve it. 
PE_{grav} =mgh
PE_{grav} =(10kg)(3.7m/s^{2})(1m)
PE_{grav} =37J


7 0
3 years ago
The drawing shows a plot of the output emf of a generator as a function of time t. The coil of this device has a cross-sectional
adell [148]

This question is incomplete, the missing image uploaded along this answer below;

Answer:

a) frequency is 2.381 Hz

b) the angular frequency/speed is 14.96 rad/s

c) the magnitude of the magnetic field is 0.5199 T

Explanation:

Given that;

cross sectional Area A = 0.018 m²

Number of turns N = 200

from the diagram. maximum time T = 0.42 sec

a) the frequency f of the generator in hertz

frequency = 1 / T

we substitute

frequency = 1 / 0.42 = 2.381 Hz

Therefore, frequency is 2.381 Hz

b)  the angular frequency in rad/s

angular speed ω = 2πf

we substitute

ω = 2π × 2.381

ω = 14.96 rad/s

Therefore, the angular frequency/speed is 14.96 rad/s

c) the magnitude of the magnetic field.

to determine the magnitude of the magnetic field, we use the following expression;

e = NBAω

from the diagram, e = 28.0 V

so we substitute

28.0 V = 200 × B × 0.018 × 14.96

28 = 53.856B

B = 28 / 53.856

B = 0.5199 T

Therefore, the magnitude of the magnetic field is 0.5199 T

6 0
3 years ago
To meet the productivity goal, you must move 75 units of product per hour. You have moved 30 units of product in 30 minutes. How
9966 [12]

Answer:

1.5 unit of product per min

Explanation:

30 units of product was moved in 30 minutes.

Number of units left = Total number of units-number of units moved

                                =75-30 =45 units

45 units is available to be moved for the rest 30 min. To be able to achieve this goal of 75 units of product per hour.

45/30 amount of units must be moved in 1 min

=1.5 unit per min

4 0
3 years ago
A spring on a horizontal surface can be stretched and held 0.2 m from its equilibrium position with a force of 16 N. a. How much
nekit [7.7K]

Answer:

a   W_{3.5} = 490 \  J

b  W_{2.5} =  250 \  J

Explanation:

Generally the force constant is mathematically represented as

       k  = \frac{F}{x}

substituting values given in the question

=>   k  = \frac{16}{0.2}

=>   k  =  80 \ N /m

Generally the workdone  in stretching the spring 3.5 m is mathematically represented as

       W_{3.5} =  \frac{1}{2}  *  k  *  (3.5)^2

=>     W_{3.5} =  \frac{1}{2}  *  80  *  (3.5)^2

=>    W_{3.5} = 490 \  J

Generally the workdone  in compressing the spring 2.5 m is mathematically represented as

        W_{2.5} =  \frac{1}{2}  *  k  *  (2.5)^2

=>      W_{2.5} =  \frac{1}{2}  *  80 *  (2.5)^2

=>       W_{2.5} =  250 \  J

5 0
2 years ago
Given: G = 6.672 × 10−11 N · m2 /kg2 Io, a satellite of Jupiter, has an orbital period of 1.24 days and an orbital radius of 4.1
Dahasolnce [82]

Answer:

Mass of Jupiter = 4.173×10^15kg

Explanation:

Using Kepler's 3rd law, it states that the orbital period T is related to the distance,r as:

T^2 = GM/4 pi × r^3

Where G = universal gravitational constant

r = radius

M = masd of jupiter

Rearranging the formular to make M the subject of formular

T^2 × 4 pi = G M × r^3

(T^2 × 4 pi) / (G× r^3) = M

(1.24^2 × 4 × 3.142) /(6.672×10^-11)(4.11×10^8)^3

M = 19.32 /6.672×10^-11)(4.11×10^8)^3

M = 19.32 / 4.63 ×10^15

M = 4.173×10^15kg

6 0
2 years ago
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