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choli [55]
3 years ago
7

If an object has a mass of 25 grams and a volume of 5 mL, then what is the density of the object?

Physics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

5

Explanation:

density = mass/volume

density = 25g /5 mL

density = 5

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A voltage is applied to a resistor,
ladessa [460]

Answer:

Explanation:

By Ohms Law, Voltage = Current * Resistance

Keeping the voltage the same and doubling the resistance, the current will be halved.

So the new current = 1.5/2 = 0.75A

6 0
3 years ago
Consider two spaceships, each traveling at 0.50c in a straight line. Ship A is moving directly away from the Sun and ship B is a
attashe74 [19]

Answer:

The velocity of the light will be 1.0c only

Explanation:

The velocity of the light measured in the case given in question will be 1.0c only.

This is due to the fact that the velocity of light is never relative. The velocity of the light is maximum

The velocity of the light cannot be scaled down in no case

Thus, the velocity of the light remains as constant.

Hence, the velocity of the light measured will be 1.0c although the ships have relative velocity.

3 0
3 years ago
An investigation was done with an electromagnetic system made from a battery and wire wrapped around a nail. Different sizes of
alex41 [277]
Dependant variable is something which you MEASURE during an experiment

So your answer would be : B
5 0
3 years ago
A planet moves fastest in its orbit around the sun when it is at which position?
Nesterboy [21]

Answer:

When it's closest to the sun.

Explanation:

The force of gravity acting on a planet is equal to its mass times its centripetal acceleration.

Fg = m v^2 / r

The force of gravity is defined by Newton's law of universal gravitation as:

Fg = mMG / r^2

Therefore:

mMG / r^2 = m v^2 / r

MG / r = v^2

v increases as r decreases.  So the planet is moving fastest when it's closest to the sun, also known as the <em>perihelion</em>.

6 0
4 years ago
Read 2 more answers
A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.8 1010 m (inside the orbit
creativ13 [48]

Answer:

Explanation:

From the given information:

Distance d_i = 4.8 \times 10^{10} \ m

Speed of the comet V_i = 9.1 \times 10^{4} \ m/s

At distance d_2 = 6 \times 10^{12} \ m

where;

mass of the sun = 1.98 \times 10^{30}

G = 6.67 \times 10^{-11}

To find the speed V_f:

Using the formula:

E_f = E_i + W \\ \\  where; \  \  W = 0  \ \  \text{since work done by surrounding is zero (0)}

E_f = E_i + 0 \\ \\  K_f + U_f = K_i + U_i  \\ \\ = \dfrac{1}{2}mV_f^2 +  \dfrac{-GMm}{d^2} =  \dfrac{1}{2}mV_i^2+ \dfrac{-GMm}{d_i} \\ \\ V_f = \sqrt{V_i^2 + 2 GM \Big [  \dfrac{1}{d_2}- \dfrac{1}{d_i}\Big ]}

V_f = \sqrt{(9.1 \times 10^{4})^2 + 2 (6.67\times 10^{-11}) *(1.98 * 10^{30} ) \Big [  \dfrac{1}{6*10^{12}}- \dfrac{1}{4.8*10^{10}}\Big ]}

\mathbf{V_f =53.125 \times 10^4 \ m/s}

3 0
3 years ago
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