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Rasek [7]
3 years ago
10

A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a consta

nt force (in contrast to the constant power in part a). if such a sports car went from zero to 28.0 mph in time 1.50 s , how long would it take to go from zero to 56.0 mph ?
Physics
1 answer:
DochEvi [55]3 years ago
5 0

<span>If the sport car is moving in a constant force, it also means constant acceleration. <span>Regardless of friction, the constant power of the engine of the sport car implies that the kinetic energy of the car increases linearly with time. Therefore, if the car went from zero to 28.0 mph in time of 1.50 seconds, then the speed of the car will increase to 3 seconds if it will go from zero to 56.0 mph.</span></span>

 

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A farmer hitches her tractor to a sled loaded with firewood and pulls it a distance
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(a) The work done by the force applied by the tractor is 79,968.47 J.

(b) The work done by the frictional force on the tractor is 55,977.93 J.

(c) The total work done by  all the forces is 23,990.54 J.

<h3>Work done by the applied force</h3>

The work done by the force applied by the tractor is calculated as follows;

W = Fd cosθ

W = (5000 x 20) x cos(36.9)

W = 79,968.47 J

<h3>Work done by frictional force</h3>

W = Ffd cosθ

W = (3500 x 20) x cos(36.9)

W = 55,977.93 J

<h3>Net work done by all the forces on the tractor</h3>

W(net) = work done by applied force  -  work done by friction force

W(net) = 79,968.47 J -  55,977.93 J

W(net) = 23,990.54 J

Learn more about work done here: brainly.com/question/25573309

#SPJ1

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1 year ago
In an aqueous solution where the H+ concentration is 1 x 10-6 M, the OH concentration must be:
vesna_86 [32]

Answer:

D. 1×10⁻⁸ M

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[H⁺] [OH⁻] = 10⁻¹⁴

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3 years ago
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