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Rasek [7]
3 years ago
10

A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a consta

nt force (in contrast to the constant power in part a). if such a sports car went from zero to 28.0 mph in time 1.50 s , how long would it take to go from zero to 56.0 mph ?
Physics
1 answer:
DochEvi [55]3 years ago
5 0

<span>If the sport car is moving in a constant force, it also means constant acceleration. <span>Regardless of friction, the constant power of the engine of the sport car implies that the kinetic energy of the car increases linearly with time. Therefore, if the car went from zero to 28.0 mph in time of 1.50 seconds, then the speed of the car will increase to 3 seconds if it will go from zero to 56.0 mph.</span></span>

 

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The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.

<h3>Angular velocity of the tire</h3>

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

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<h3>Tangential velocity of the tire</h3>

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The magnitude of the tangential velocity is caculated as follows;

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