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Rasek [7]
3 years ago
10

A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a consta

nt force (in contrast to the constant power in part a). if such a sports car went from zero to 28.0 mph in time 1.50 s , how long would it take to go from zero to 56.0 mph ?
Physics
1 answer:
DochEvi [55]3 years ago
5 0

<span>If the sport car is moving in a constant force, it also means constant acceleration. <span>Regardless of friction, the constant power of the engine of the sport car implies that the kinetic energy of the car increases linearly with time. Therefore, if the car went from zero to 28.0 mph in time of 1.50 seconds, then the speed of the car will increase to 3 seconds if it will go from zero to 56.0 mph.</span></span>

 

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a motorcycle starts from rest covers 200 meter distance in 6 second calculate final velocity and acceleration​
Ivanshal [37]

Explanation:

s = ut + 1/2 a t^2

200 = 0 * 6 + 1/2 * a * (6)^2

200 = 1/2 * a * 36

200 = 18 a

a = 200/18

a= 11.1m/sec^2

v = u + at

v = 0 + 11.1 * 6

v = 66.6m/s

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3 0
2 years ago
how many times does the kinectic energy of a car increase when traveling 60 mph as opposed to traveling 30 mph
Bumek [7]
The car at 60 kph has 9 times more kinetic energy than the car traveling at 20 kph. This assumes that both cars have the same mass. Kinetic energy depends on the square of thee speed so if one car is going 3 times faster, its kinetic energy will be 3^2 ( = 9 ) greater. The car going at 60 kph will have 4 times the KE of the car going at 30 kph ( again assuming that the cars have the same mass.)
3 0
3 years ago
[100 POINTS] Which of the following do not make their own energy through nuclear fusion? Select all that apply.
Ksenya-84 [330]

Answer:

The correct answer is :

A . Giant star

B . proto star

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Explanation:

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7 0
3 years ago
Read 2 more answers
Imma give u all my points and ill make u brainlist jus answer them​
Reptile [31]

I'll put my answer in the comments but, part of the question is cut off do you mind putting a more readable and not sideways picture?

3 0
3 years ago
A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

    (m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

                 k = [(m)×(v^2)]/(x^2)

                 k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

                 k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

             v^2 = [(k)(x^2)]/m

                 v =  \sqrt{ [(k)(x^2)]/m}

                 v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

                    = 0.491 m/s

8 0
2 years ago
Read 2 more answers
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