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Aloiza [94]
3 years ago
11

The usa flag..........

Chemistry
1 answer:
sammy [17]3 years ago
5 0

Answer:

lol

Explanation:

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1 year ago
Place the following substance in order of increasing vapor pressure at a given temperature
Dmitrij [34]

Answer: ok that was i am doing

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5 0
4 years ago
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Answer:

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8 0
3 years ago
How many moles of ammonium nitrate are there in 32.5 mL of<br> a0.125 M NH4NO3 solution?
Nady [450]

<u>Answer:</u> The number of moles of ammonium nitrate is 0.004 moles.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

We are given:

Molarity of NH_4NO_3 solution = 0.125 M

Volume of solution = 32.5 mL

Putting values in above equation, we get:

0.125M=\frac{\text{Moles of }NH_4NO_3\times 1000}{32.5mL}\\\\\text{Moles of }NH_4NO_3=0.004mol

Hence, the number of moles of ammonium nitrate is 0.004 moles.

8 0
4 years ago
Please help me thank you.
Semmy [17]
I will show you with detailed work for NaCl, but follow the same procedure for the rest of the compounds.

Molar Mass - Find the molar mass of the Na and the Cl and add them together
Na - 23
Cl - 35.5
Add those numbers together 23 + 35.5 = 58.5 g/mol

Moles in 1 tsp:
The mass measured in 1tsp of NaCl was 18 g.  To calculate the amount of moles you take the mass measured and divide it by the molecular weight.
18/58.5 = 0.3077 mol

Moles of each element:
To find the moles each element in the compound you multiply the moles of 1 tsp by the number of atoms of the element in the compound
Na - 1 in NaCl
Cl - 1 in Na Cl
so take 0.3077 * 1 = 0.3077 moles Na (and Cl in this case)

Atoms of each:
take the number of moles calculated and multiply that by Avogadro's number(6.023x10^23) for the number of molecules
So for both Na and Cl:
0.3077 * 6.023x10^23 = 1.853x10^23 atoms for both Na and Cl
7 0
4 years ago
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