Answer:
A bag of blood with a density of 1050 kg/m4 is raised about 1.00 m higher than the level of a patient's arm. How much greater is the blood pressure at the patient's arm than it would be if the bag were at the same height as the army is the solisan of kind
Hello!!
The Answer is A! Motor.
Hope this helps ~Nayiah~
Answer:
1 / i + 1 / o = 1 / f thin lens equations
i = o f / (o - f) rearranging
Lens 1: object = 30 cm f = 15.2 cm
i1 = 30 * 15.2 / (30 - 15.2) = 30.8 cm
o2 = 40.2 - 30/8 = 9.4 cm distance of image 1 from lens 2
i2 = 9.4 * 15.2 / (9.4 - 15.2) = - 24.6 cm
The final image is 24.6 cm to the left of lens 2
The first image is inverted
The second image is erect (as seen from the first image)
So the final image is inverted
M = m1 * m2 = (-30.8 / 30) * (24.6 / 9.4) = -2.69
<span>The common designations are radio waves, microwaves, infrared (IR), visible light, ultraviolet (UV), X-rays and gamma-rays. Visible light falls in the rangeof the EM spectrum between infrared (IR) and ultraviolet (UV).</span>
Answer:
Q = 50.25 [J]
Explanation:
To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.
Q = m*Cp*(DT)
where:
Q = energy in form of heat [J]
m = mass = 5 [g] = 0.005 [kg]
Cp = specific heat = 1005 [J/kg*°C]
DT = temperature change = 10 [°C]
Now replacing:
Q = 0.005*1005*10
Q = 50.25 [J]
