how height does a 2.5 Kg object rises when 255J of work done against gravity A 637.5 B 20.5 C 15m D 10.2 m
2 answers:
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Power =
Delilah: 170J/30s = 5.66 W
Adam: 260J/20s = 13 W
Answer:
K = 0.076 J
Explanation:
The height of the target, h = 0.860 m
The mass of the steel ball, m = 0.0120 kg
Distance moved, d = 1.50 m
We need to find the kinetic energy (in joules) of the target ball just after it is struck. Let t is the time taken by the ball to reach the ground.
Put all the values,
The velocity of the ball is :
The kinetic energy of the ball is :
So, the required kinetic energy is 0.076 J.