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ivolga24 [154]
3 years ago
9

how height does a 2.5 Kg object rises when 255J of work done against gravity A 637.5 B 20.5 C 15m D 10.2 m​

Physics
2 answers:
xz_007 [3.2K]3 years ago
8 0

Answer:

D

Explanation:

Work = Mass * Gravity(9.8) * Height

height=work/(mass*9.8)

height=255/(2.5*9.8)=10.4m

balu736 [363]3 years ago
7 0

Answer:

D 10.2

Explanation:

255 ÷ 2.5= 10.2 or D

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Answer:

U_{b}=+7.3*10^{-8}J

Explanation:

Given data

Electric potential at point a is Ua=5.4×10⁻⁸J

q₂ moves to point b where a negative work done on it  W_{a-b}=-1.9*10^{-8}J

Required

Electric potential energy Ub

Solution

When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:

W_{a-b}=U_{a}-U_{b}\\U_{b}=U_{a}-W_{a-b}

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Sound travels through a ​
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A coil with an inductance of 2.8 H and a resistance of 12 Ω is suddenly connected to an ideal battery with ε = 89 V. At 0.086 s
Thepotemich [5.8K]

Answer:

The stored energy is 140.7 watt.

The thermal energy is 62.7 watt.

The delivered energy is 203.4 watt.

Explanation:

Given that,

Inductance = 2.8 H

Resistance = 12 Ω

Potential \epsilon_{0}=89\ V

Time = 0.086 s

(a). We need to calculate the energy stored in the magnetic field

Using formula of current

i=i_{max}(1-e^(\frac{-t}{\tau}))

Using formula of energy

U=\dfrac{1}{2}Li^2

On differentiating

\dfrac{dU}{dt}=Li\frac{di}{dt}

\dfrac{dU}{dt}=L\dfrac{d}{dt}(i_{max}(1-e^(\frac{-t}{\tau}))

Again differentiating

\dfrac{dU}{dt}=\dfrac{\epsilon^2}{R}(1-e^{\frac{-t}{\tau}})e^{\frac{-t}{\tau}}

\dfrac{dU}{dt}=\dfrac{\epsilon^2}{R}(1-e^{\frac{-\t\times R}{L}})e^{\frac{-t\times R}{L}}

Put the value into the formula

\dfrac{dU}{dt}=\dfrac{(89)^2}{12}(1-e^{\dfrac{-0.086\times12}{2.8}})e^{\dfrac{-0.086\times12}{2.8}}

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Using formula of thermal energy

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P=\dfrac{\epsilon^2}{R}(1-e^{\frac{-t}{\tau}})^2

Put the value into the formula

P=\dfrac{89^2}{12}(1-e^{\dfrac{-0.086\times12}{2.8}})^2

P=62.7\ Watt

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Using formula of energy

P'=P+\dfrac{dU}{dt}

P'=62.7+140.7

P'=203.4\ watt

Hence, The stored energy is 140.7 watt.

The thermal energy is 62.7 watt.

The delivered energy is 203.4 watt.

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