Answer:

Explanation:
Given data
Electric potential at point a is Ua=5.4×10⁻⁸J
q₂ moves to point b where a negative work done on it
Required
Electric potential energy Ub
Solution
When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:

Now substitute the given values
So

Answer:
A.3.64 m
Explanation:
Because
- v=(fλ)
- (1382)=(380)λ
- λ=3.637m~3.64m
<em>where</em><em> </em><em>,</em><em>v</em><em>=</em><em>velocity</em>
<em>f</em><em>=</em><em>frequency</em><em> </em>
<em>λ</em><em>=</em><em>wave</em><em> </em><em>length</em><em> </em>
True
From what Ive learned its like how you create your own hypothesis for a science experiment it may not work completely that way but you learn what didnt work and what does work
Answer:
The stored energy is 140.7 watt.
The thermal energy is 62.7 watt.
The delivered energy is 203.4 watt.
Explanation:
Given that,
Inductance = 2.8 H
Resistance = 12 Ω
Potential 
Time = 0.086 s
(a). We need to calculate the energy stored in the magnetic field
Using formula of current

Using formula of energy

On differentiating


Again differentiating


Put the value into the formula


(b). We need to calculate the thermal energy
Using formula of thermal energy


Put the value into the formula


(c). We need to calculate the delivered energy by the battery
Using formula of energy



Hence, The stored energy is 140.7 watt.
The thermal energy is 62.7 watt.
The delivered energy is 203.4 watt.