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3 years ago

how height does a 2.5 Kg object rises when 255J of work done against gravity A 637.5 B 20.5 C 15m D 10.2 m

Physics

2 answers:

xz_007 [3.2K]3 years ago

8 0

Answer:

Explanation:

Work = Mass * Gravity(9.8) * Height

height=work/(mass*9.8)

height=255/(2.5*9.8)=10.4m

balu736 [363]3 years ago

7 0

Answer:

D 10.2

Explanation:

255 ÷ 2.5= 10.2 or D

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A. To find the total emf of the battery, just remember that in a parallel circuit, the voltage is the same throughout the circuit. So you can get the total voltage of the circuit by using Ohm's Law.

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I = current (A)
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R = Resitance (Ω)

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You have three resistors with the following resistance:
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$\frac{1}{R_{T}} = \frac{1}{R_{1}}+ \frac{1}{R_{2}}+ \frac{1}{R_{3}}...+ \frac{1}{R_{n}}$

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$V = (1.8)(16.32)$
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B. To find the resistance in each resistor, just apply Ohm's law again. In a parallel circuit, the voltage is the same, but the current that runs through it is different for each resistor. Now just solve for the current of each using the same voltage.

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The current flowing through resistor 1 with a resistance of 65Ω is 0.45A.

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$I= \frac{29.376}{25}$
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The current flowing through resistor 2 with a resistance of 25Ω is 1.18A.

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$I= \frac{29.376}{170}$
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The current flowing through resistor 3 with a resistance of 170Ω is 0.17A.

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how height does a 2.5 Kg object rises when 255J of work done against gravity A 637.5 B 20.5 C 15m D 10.2 m​

how height does a 2.5 Kg object rises when 255J of work done against gravity A 637.5 B 20.5 C 15m D 10.2 m