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3 years ago

Which of these best describes how the kinetic energy of carbon dioxide molecules change as the carbon dioxide is heated?

Physics

2 answers:

Yuliya22 [10]3 years ago

5 0

Answer: The correct answer is Option B.

Explanation:

Kinetic energy is defined as the energy which is possessed by the motion of a particle. The formula for the kinetic energy follows:

$K.E.=\frac{3}{2}\frac{R}{N_A}T$

where, R = Gas Constant

$N_A=\text{Avogadro's Number}$

T = Temperature

From above expression, kinetic energy is directly proportional to temperature of the system

$\text{Kinetic energy}\propto \text{Temperature}$

As the temperature is increases, the kinetic energy of the particles also increases and vice-versa.

In the given question,

The gas (carbon-dioxide) is heated which means the temperature of the gas is increases and hence, the kinetic energy will also be increased.

Hence, the correct answer is Option B.

spin [16.1K]3 years ago

4 0

B.
carbon dioxide molecules have more energy; therefore, the kinetic energy increases

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The magnitude of the gravitational field strength near Earth's surface is represented by

Zanzabum

Answer:

The magnitude of the gravitational field strength near Earth's surface is represented by approximately $9.82\,\frac{m}{s^{2}}$ .

Explanation:

Let be M and m the masses of the planet and a person standing on the surface of the planet, so that M >> m. The attraction force between the planet and the person is represented by the Newton's Law of Gravitation:

$F = G\cdot \frac{M\cdot m}{r^{2}}$

Where:

$M$ - Mass of the planet Earth, measured in kilograms.

$m$ - Mass of the person, measured in kilograms.

$r$ - Radius of the Earth, measured in meters.

$G$ - Gravitational constant, measured in $\frac{m^{3}}{kg\cdot s^{2}}$ .

But also, the magnitude of the gravitational field is given by the definition of weight, that is:

$F = m \cdot g$

Where:

$m$ - Mass of the person, measured in kilograms.

$g$ - Gravity constant, measured in meters per square second.

After comparing this expression with the first one, the following equivalence is found:

$g = \frac{G\cdot M}{r^{2}}$

Given that $G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}$ , $M = 5.972 \times 10^{24}\,kg$ and $r = 6.371 \times 10^{6}\,m$ , the magnitude of the gravitational field near Earth's surface is:

$g = \frac{\left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (5.972\times 10^{24}\,kg)}{(6.371\times 10^{6}\,m)^{2}}$

$g \approx 9.82\,\frac{m}{s^{2}}$

The magnitude of the gravitational field strength near Earth's surface is represented by approximately $9.82\,\frac{m}{s^{2}}$ .

4 0

3 years ago

A student is performing experiments on a particular substance. Which

boyakko [2]

Answer: A.

Explanation:

6 0

2 years ago

Q 6: A body throws a ball vertically up. It returns to the ground after 5 seconds. Find

Rasek [7]

Answer:

Taking gravity to be 9.8m/s2, The velocity is 24.5m/s2.

Taking gravity to be 10m/s2, The velocity is 25m/s2.

Explanation:

According the first formula of motion under the influence of gravity for upward motion, v=u-gt, where v=final velocity, u=initial velocity, and t= time taken.

Here the time taken for the ball to reach the maximum point is half of 5, which is 2.5 seconds.

And v is 0, since at the maximum point gravity slows down the velocity to 0.

Finding the initial velocity,

v=u-gt

0=u-10(2.5)

u=10(2.5)

u=25m/s

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2 years ago

A bicycle is traveling north at 5.0 m/s. The mass of the wheel, 2.0 kg, is uniformly distributed along the rim, which has a radi

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