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Helen [10]
3 years ago
13

If nitrogen gas is collected over water at 20 o C and the total pressure of the gas in the collection vessel is 200 kPa, what is

the pressure of dry nitrogen gas?
Chemistry
1 answer:
Citrus2011 [14]3 years ago
8 0

Answer:

Explanation:

pressure of dry nitrogen gas at 20° = Partial pressure of nitrogen and partial pressure of water at that temperature .

The pressure of dry nitrogen gas= total pressure - vapour pressure of water at 20°C

= 200 k Pa - 2.34 k Pa

= 197.66 kPa.

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A mixture containing nitrogen and hydrogen weighs 3.49 g and occupies a volume of 7.45 L at 305 K and 1.03 atm. Calculate the ma
-BARSIC- [3]

Answer:

Mass percent N₂ = 89%

Mass percent H₂ = 11%

Explanation:

First we <u>use PV=nRT to calculate n</u>, which is the total number of moles of nitrogen and hydrogen:

  • 1.03 atm * 7.45 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305 K
  • n = 0.307 mol

So now we know that

  • MolH₂ + MolN₂ = 0.307 mol

and

  • MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49 g

So we have a <u>system of two equations and two unknowns</u>. We use algebra to solve it:

Express MolH₂ in terms of MolN₂:

  • MolH₂ + MolN₂ = 0.307 mol
  • MolH₂ = 0.307 - MolN₂

Replace that value in the second equation:

  • MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49
  • (0.307-MolN₂) * 2 + MolN₂ * 28 = 3.49
  • 0.614 - 2MolN₂ + 28molN₂ = 3.49
  • 0.614 + 26MolN₂ = 3.49
  • MolN₂ = 0.111 mol

Now we calculate MolH₂:

  • MolH₂ + MolN₂ = 0.307 mol
  • MolH₂ + 0.111 = 0.307
  • MolH₂ = 0.196 mol

Finally, we convert each of those mol numbers to mass, to <u>calculate the mass percent</u>:

  • N₂ ⇒ 0.111 mol * 28 g/mol = 3.108 g N₂
  • H₂ ⇒ 0.196 mol * 2 g/mol = 0.392 g H₂

Mass % N₂ = 3.108/3.49 * 100% = 89.05% ≅ 89%

Mass % H₂ = 0.392/3.49 * 100% = 11.15% ≅ 11%

5 0
3 years ago
An example of an ____ reaction is when metals react with oxygen to form metal _____.​
Reptile [31]

<em>An example of a</em><em>n</em><em> </em><em><u>exothermic</u></em><em> </em><em>reaction is when metals react with oxygen to form metal</em><em> </em><em><u>Oxides</u></em>

<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em>helped you- have a good day bro cya)

4 0
3 years ago
Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. ____CO +____ O2 → ____CO2
Black_prince [1.1K]
<h3><u>Answer;</u></h3>

2, Blank, 2 ;

<h3><u>Explanation;</u></h3>

The balanced chemical equation would be;

2 CO + O2 → 2 CO2

Balancing a chemical equation ensures that the number of atoms of each element are equal on both the reactants side and the products side. This ensures that the law of conservation of mass is obeyed in chemical reactions.

4 0
3 years ago
Read 2 more answers
A 28.5 gram piece of iron is added to a graduated cylinder containing 45.5 mL of water. The water in the cylinder rises to the 4
yan [13]

7.91 g/ml is the density of the iron piece of 28.5 gms.

Explanation:

The density of a substance is defined as the volume it occupies.  It tells the matter present in a substance.

The density is mass per unit volume and is denoted by p.

The formula for density is given by:

density (p) = \frac{mass}{volume}

Data given is :

mass= 28.5 grams

V1 = 45.5 ml

V2= 49.1 ml

The initial volume of water was 45.5 ml, when iron piece of 28.5 grams was added the final volume was 49.1 ml.

Putting the values in the equation of density

p = \frac{28.5}{49.1-45.5}

p = 7.91 g/ml

Since iron is a dense material it will occupy less volume

4 0
3 years ago
which of the following testable questions will provide evidence that elements in the same group have similar properties?
Usimov [2.4K]

The testable question which will provide evidence that elements in the same group have similar properties is valency

<h3>What is the valency?</h3>

In essence, how many electrons are present in their outermost shell.

Valency and Groups in the periodic table, elements are arranged in order of their atomic numbers and hence, the periodic table is a systematic arrangement of elements in an array of vertical columns called Groups and horizontal arrays called Periods.

  • Complete question here:

which of the following testable questions will provide evidence that elements in the same group have similar properties A. Valency B. Orbit C. Group D. Period

Since, the reactive capacities of elements is dependent on the number of electrons on its outermost shell, we can conclude on this note that, Elements in the same group have similar properties.

Learn more on Groups and Valency:

brainly.com/question/1645905

4 0
2 years ago
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