Answer:
Henry's law constant for a gas ch3br
28 The Henry's Law constant of methyl bromide, CH3Br, is k = 0.159 mol/(L⋅atm) at 25°C.
Explanation:
Answer:
In explanation
Explanation:
a. Selenium, atomic number 34
Argon is 18, adding the other electrons gives 34.
Other elements include: oxygen O , Sulphur S , Tellurium Te and Polonium Po
b. Hafnium, element 72
Xe is 54, adding the other electrons makes the total 72.
Other elements; Titanium Ti, Zirconium Zr, Rutherfordium Rf
c. Manganese, element 25
Other group members are Technetium Tc , Rhenium Re and Bohrium Bo
A non cyclic alkane always has a number of hydrogen atoms equal to 2c + 2, where c is the number of carbon atoms. Therefore, hexadecane, an alkane with 15 carbon atoms, will have 32 hydrogen atoms.
Answer: A - Propanone and ethanal.
Explanation:
Aldol condensation may be defiend as a reaction which involves an enol or an enolate ion with a carbonyl compound to form a beta-hydroxyaldehyde (β-hydroxyaldehyde or β-hydroxyketone), which is accompanied by dehydration to give a conjugated enone.
In this case, Propanone and ethanal will undergo condensation reaction to produce pent-3-ene-2-one.
It is important to note that propanone is an enol.
Therefore, the pair of reactants that will undergo aldol condensation to produce pent-3-ene-2-one? is Propanone and ethanal.
I believe it’s f sorry if I’m incorrect
