Answer:
Given
inlet Pga =40kpa = 40000pa
Patm=1.01bar = 1.01 x 100000pa =101000pa
exit Pab= 6.5 (inlet Pab)
But generally, Pab = Patm + Pga
1. the absolute pressure of the gas at the inlet, inlet Pab?
inlet Pab = Patm + inlet Pga
= 101000pa + 40000pa = 141kpa
the absolute pressure of the gas at the inlet, inlet Pab = 141kpa
2. the gage pressure of the gas at the exit? exit Pga?
exit Pab = Patm + exit Pga
exit Pga = exit Pab - Patm
= (6.5 x 141kpa) - 101kpa
= 815.5kpa
the gage pressure of the gas at the exit exit Pga=815.5kpa
