Answer:
I don't know ☺️☺️☺️❌‼️
Explanation:
I don't understand this question
Answer:
I would say an Oblique drawing.
Explanation:
An oblique drawing uses 45 degree angles.
Given:
Pressure,
= 1300 kPa
Temperature,
= 
= 100 kPa
velocity, v = 40 m/s
A = 1
Solution:
For air propertiess at
= 1300 kPa
= 
= 793kJ/K
= 
and also at
= 100 kPa
= 401 KJ/K
= 
a) Mass flow rate is given by:

Now,
= 46.51 kg/s
b) for the power produced by turbine, 
= 18.231 MW
Answer:) The correct answer is B. at the end of the fuel rail.
2) The one who is correct is the Technician A.
Explanation:
Answer:
The lowest outdoor temperature for which the heat pump can meet the requirement of the house is -9.6°C
Explanation:
The coefficient of performance of a heat pump, COP, is given by the relation;

The rate of heat loss
= 3800 kJ/h = 3800 ×1/60 × 1/60 kJ/s = 1.06 kJ/s
The power input = 4 kW = 4 kJ/s
The temperature indoors = 24 + 273.15 = 297.15 K
Therefore, we have;

4×297.15= (297.15- T₁) × 1.06×(297.15- T₁)
Which gives;
18/19·T₁²-627.32·T₁+92014.97=0
(T₁ -263.59)·(T₁ - 330.71) = 0
The solutions are;
T₁ = 263.59 K or T₁ = 330.71 K
The lowest temperature = 263.59 K which is -9.6°C
The lowest temperature = -9.6°C.