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nikitadnepr [17]
2 years ago
6

Do you think that individuals with the same disabilities have the same needs? If your answer is yes, how? /No, why?​

Engineering
1 answer:
Blababa [14]2 years ago
5 0

Disability is extremely diverse. While some health conditions associated with disability result in poor health and extensive health care needs, others do not. However, all people with disability have the same general health care needs as everyone else, and therefore need access to mainstream health care services.

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3. What is the mechanical advantage of the pulley system shown below? HII TAI 190 O A1 O E.2 OC.3 OD 4​
Contact [7]

Answer:

I don't know ☺️☺️☺️❌‼️

Explanation:

I don't understand this question

7 0
3 years ago
What type of drawing would civil engineers use if they needed to show an
Katyanochek1 [597]

Answer:

I would say an Oblique drawing.

Explanation:

An oblique drawing uses 45 degree angles.

5 0
4 years ago
An adiabatic gas turbine expands air at 1300 kPa and 500◦C to 100 kPa and 127◦C. Air enters the turbine through a 0.2-m2 opening
Viktor [21]

Given:

Pressure, P_{1} = 1300 kPa

Temperature,  T_{1} = 500^{\circ}

P_{2} = 100 kPa

T_{2} = 127^{\circ}  

velocity, v = 40 m/s

A = 1m^{2}

Solution:

For air propertiess at

P_{1} = 1300 kPa

T_{1} = 500^{\circ}

h_{1} = 793kJ/K

v_{1} = 0.172\frac{m^{3}}{kg}

and also at

P_{2} = 100 kPa

T_{2} = 127^{\circ}  

h_{2} = 401 KJ/K

v_{2} =  1.15\frac{m^{3}}{kg}

a) Mass flow rate is given by:

m' = \frac{Av}{v_{1}}

Now,

m = \frac{0.2\times 40}{0.172} = 46.51 kg/s

b) for the power produced by turbine, P = m'(h_{1} - h_{2})

P = 46.51\times(793 - 401) = 18.231 MW

5 0
4 years ago
Fuel filters are being replaced on a HPCR diesel
saw5 [17]

Answer:) The correct answer is B. at the end of the fuel rail.

2) The one who is correct is the Technician A.

Explanation:

7 0
4 years ago
The structure of a house is such that it loses heat ata rate of 3800 kJ/h per8C difference between the indoors andoutdoors. A he
marysya [2.9K]

Answer:

The lowest outdoor temperature for which the heat pump can meet the requirement of the house is -9.6°C

Explanation:

The coefficient of performance of a heat pump, COP, is given by the relation;

COP_{hp} = \dfrac{T_2}{T_2 - T_1} = \dfrac{Q_1\times (T_2 - T_1)}{\Sigma W}

The rate of heat loss \dot Q_1 = 3800 kJ/h = 3800 ×1/60 × 1/60 kJ/s = 1.06 kJ/s

The power input = 4 kW = 4 kJ/s

The temperature indoors = 24 + 273.15 = 297.15 K

Therefore, we have;

COP_{hp} = \dfrac{297.15}{297.15- T_1} = \dfrac{1.06 \times (297.15- T_1)}{4}

4×297.15= (297.15- T₁) × 1.06×(297.15- T₁)

Which gives;

18/19·T₁²-627.32·T₁+92014.97=0

(T₁ -263.59)·(T₁ - 330.71) = 0

The solutions are;

T₁ = 263.59 K or T₁ = 330.71 K

The lowest temperature = 263.59 K which is -9.6°C

The lowest temperature = -9.6°C.

4 0
3 years ago
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