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2 years ago

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The gage pressure measured as 2.2 atm, the absolute pressure of gas is 3.2 bar. Please determine the local atmospheric pressure

in kPa.

1 answer:

LiRa [457]2 years ago

8 0

Answer:

$97.085\ \text{kPa}$

Explanation:

$P_{g}$ = Gauge pressure = 2.2 atm = $2.2\times 101325=222915\ \text{Pa}$

$P_{abs}$ = Absolute pressure = $3.2\ \text{bar}=3.2\times 10^5\ \text{Pa}$

$P_{atm}$ = Local atmospheric pressure

Absolute pressure is given by

$P_{abs}=P_{atm}+P_g\\\Rightarrow P_{atm}=P_{abs}-P_g\\\Rightarrow P_{atm}=3.2\times 10^5-222915\\\Rightarrow P_{atm}=97085\ \text{Pa}=97.085\ \text{kPa}$

The local atmospheric pressure is $97.085\ \text{kPa}$ .

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Based on the Chvorinov's rule, the diference in the <em>solidification</em> times of the two castings is 14.092 times the <em>solidification</em> time of the prism casting.

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The Chvorinov's rule is an empirical method to estimate the cooling time of a casting in terms of a <em>reference</em> time. This rule states that cooling time (<em>t</em>) is directly proportional to the square of the volume (<em>V</em>), in cubic meters, divided to the surface area (<em>A</em>), in square meters. Now we proceed to model each casting:

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