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Ratling [72]
3 years ago
14

The gage pressure measured as 2.2 atm, the absolute pressure of gas is 3.2 bar. Please determine the local atmospheric pressure

in kPa.
Engineering
1 answer:
LiRa [457]3 years ago
8 0

Answer:

97.085\ \text{kPa}

Explanation:

P_{g} = Gauge pressure = 2.2 atm = 2.2\times 101325=222915\ \text{Pa}

P_{abs} = Absolute pressure = 3.2\ \text{bar}=3.2\times 10^5\ \text{Pa}

P_{atm} = Local atmospheric pressure

Absolute pressure is given by

P_{abs}=P_{atm}+P_g\\\Rightarrow P_{atm}=P_{abs}-P_g\\\Rightarrow P_{atm}=3.2\times 10^5-222915\\\Rightarrow P_{atm}=97085\ \text{Pa}=97.085\ \text{kPa}

The local atmospheric pressure is 97.085\ \text{kPa}.

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Answer:

A) W' = 15680 KW

B) W' = 17113.87 KW

Explanation:

We are given;

Temperature at state 1; T1 = 290 K

Temperature at state 3; T3 = 1100 K

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Now, we don't have T4 and T2 but they can be gotten from;

T4 = [T3 × (r_p)^((1 - k)/k)]

T2 = [T1 × (r_p)^((k - 1)/k)]

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r_p = 760/95

r_p = 8

Also,k which is specific heat capacity of air has a constant value of 1.4

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Plugging in the relevant values, we have;

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B) The power accounting for the variation of specific heats with temperature is given by;

W' = [1 - ((h4 - h1)/(h3 - h2))] × Q_in

From the table attached, we have the following;

At temperature of 607.25 K and by interpolation; h4 = 614.64 KJ/K

At T3 = 1100 K, h3 = 1161.07 KJ/K

At T1 = 290 K, h1 = 290.16 KJ/K

At T2 = 525.32 K, and by interpolation, h2 = 526.12 KJ/K

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