Given the data from the question, the final temperature is 200 K, while pressure remains constant.
<h3>Basic concepts </h3>
To obtain the correct answer to the question, we shall consider two conditions:
- Case 1 (temperature is constant)
- Case 2 (pressure is constant)
<h3>Case 1 (Temperature is constant) </h3>
We shall determine the new pressure by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:
- Initial volume (V₁) = 3 L
- Initial pressure (P₁) = 1 atm
- Temperature = constant
- New Volume (V₂) = 2 L
- New pressure (P₂) =?
P₁V₁ / T₁ = P₂V₂ / T₂
Since temperature is constant, we have:
P₁V₁ = P₂V₂
3 × 1 = P₂ × 2
3 = P₂ × 2
Divide both side by 2
P₂ = 3 / 2
P₂ = 1.5 atm
<h3>Case 2 ( pressure is constant) </h3>
We shall determine the new temperature by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:
- Initial volume (V₁) = 3 L
- Initial pressure (T₁) = 300 K
- Pressure = constant
- New Volume (V₂) = 2 L
- New pressure (T₂) =?
P₁V₁ / T₁ = P₂V₂ / T₂
Since pressure is constant, we have:
V₁ / T₁ = V₂ / T₂
3 / 300 = 2 / T₂
1 / 100 = 2 / T₂
Cross multiply
T₂ = 100 × 2
T₂ = 200 K
SUMMARY
- when the temperature is constant, the new pressure is 1.5 atm
- When the pressure is constant, the new temperature is 200 K
From the calculations made above, we can conclude that the correct answer is:
The final temperature is 200 K, while pressure remains constant.
Learn more about gas laws:
brainly.com/question/6844441
Hello there,
The number placed below an element's symbol in a chemical formula is called....
a subscript
Hope I Helped!
-Char
Answer:
1.95mol
Explanation:
First let us generate the equation for the reaction:
2H2 + O2 —> 2H2O
From the equation,
1mole of O2 reacted to produce 2moles of H2O.
Therefore, Xmol of O2 will react to produce 3.9 mol of H2O i.e
Xmol of O2 = 3.9/2 = 1.95mol
<span>The noble gas notation is as follows- you must start with the noble gas that is before the element which in this case is Krypton and then from there you continue the electron configuration as follows- [Kr] 5s^2 4d^10 5p^2</span>