We have that the speed of the ice at the bottom is mathematically given as
v=1.8812m/s
<h3>The speed of the ice at the bottom </h3>
Question Parameters:
A 8.00 kg block of ice, released from rest
at the top of a 1.50-m-long frictionless ramp,
slides downhill, reaching a speed of 2.70 m/s
constant friction force of 10.0 N parallel to the surface of the ramp
Generally the equation for the Potential Energy is is mathematically given as
P.E=K.E+W_{fric}
Therefore
mgh=0.5mv^2+W_{fric}
Where
W_{fric}=F.S
W_{fric}=10*1.50
W_{fric}=15
And
mgh=0.5mv^2+
h=0.3719
Hence
0.5(8.00)(v^2)=(8.00)(9.8)(0.3719)-15
v^2=3.53924
v=1.8812m/s
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The Juan de fuca ridge is a mid-ocean spreading center and divergent plate boundary located off the coast of the Pacific Northwest region of North America.
the driftwood is moving up and down because the wave is transferring energy to it. there is no transfer of matter because every molecule stays in its horizontal position moving only up and down. had there been a transfer of matter then the drift wood would have moved towards the shore.
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Answer:
Force = 22508.86 N
Explanation:
Given:
Area of the window, A = 2.02 m²
Air pressure inside the house, P₁ = 1.02 atm
External air pressure, P₂ = 0.910 atm
Now, The difference in the pressure, ΔP = P₁ - P₂ = 1.02 - 0.910 = 0.11 atm
or
ΔP = 0.11 atm × (101300 Pa / 1 atm )
ΔP = 11143 Pascals
Now,
the Force is given as:
Force = Pressure × area
on substituting the values, we get
Force = 11143 Pa × 2.02 m²
or
Force = 22508.86 N
Answer: The cricket ball bc of the material
Explanation:
