Answer:
v = 10 m/s
Explanation:
Let's assume the wheel does not slip as it accelerates.
Energy theory is more straightforward than kinematics in my opinion.
Work done on the wheel
W = Fd = 45(12) = 540 J
Some is converted to potential energy
PE = mgh = 4(9.8)12sin30 = 235.2 J
As there is no friction mentioned, the remainder is kinetic energy
KE = 540 - 235.2 = 304.8 J
KE = ½mv² + ½Iω²
ω = v/R
KE = ½mv² + ½I(v/R)² = ½(m + I/R²)v²
v = √(2KE / (m + I/R²))
v = √(2(304.8) / (4 + 0.5/0.5²)) = √101.6
v = 10.07968...
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Car, computer,drill,air plane,television, vending machine
Answer:
The gravitational potential energy of the two-sphere system just as B is released is
U = -[(G)(MA)(MB)/x₁]
where G = Gravitational constant
G = (6.7 × 10⁻¹¹) Nm²/kg²
Explanation:
The gravitational potential energy of two masses (m and M), separated by a distance, d, is given as
U = -(GMm/d)
For our question,
Mass of object 1 = MA
Mass of object 2 = MB
Distance between them = x₁
U = -[(G)(MA)(MB)/x₁]
where G = Gravitational constant
G = (6.7 × 10⁻¹¹) Nm²/kg²
Hope this Helps!!!
