Use Net Force Equation.
Fnet = F1 + F2 + F3 + F4
In which the following main forces in play are:
F1 = Gravitational Force
F2 = Normal Force
F3 = Thrust Force
F4 = Air resistance
Since this is assumed to happen on a flat surface, the gravitational and normal forces cancel out. So we are left with:
Fnet = F(thrust) + F(air resistance)
Now we can use this equation to solve for the net force.
Fnet = 10N [right] + 7N [left]
Fnet = 10N [right] - 7N [right]
Fnet = 3N [right].
Therefore, the total net force acting on this car would be 3N [right]
Answer:
value of fs,max under the circumstances is
f = 42.56 N
Explanation:
The formula is µ = f / N, where µ is the coefficient of friction, f is the amount of force that resists motion, and N is the normal force. Normal force is the force at which one surface is being pushed into another.
So f = µN
f = 0.380 * 112
f = 42.56 N
Answer:
Fx = 35.36 N
Fy = 35.36 N
Explanation:
From the question,
The X component of the force is
Fx = Fcos∅.................. Equation 1
Where Fx = X component of the force, F = Force, ∅ = Angle to the horizontal.
Give: F = 50 N, ∅ = 45°
Substitute into equation 1
Fx = 50(cos45°)
Fx = 50(0.7071)
Fx = 35.36 N
Similarly,
For Y component
Fy = Fsin∅
Where F y = Y component
Fy = 50(sin45°)
Fy = 50(0.7071)
Fy = 35.36 N
Answer:
Explanation:
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Answer:

Explanation:
Given that,
Mass of the object, m = 100 grams
Volume of the object, V = 20 cm³
We need to find the density of the object. We know that, density is equal to mass per unit volume. So,

So, the density of the object is equal to
.