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Fofino [41]
3 years ago
13

An automobile of mass 1300 kg has an initial velocity of 7.20 m/s toward the north and a final velocity of 6.50 m/s toward the w

est. The magnitude and direction of the change in momentum of the car are?
Physics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Answer

given,

mass of the automobile = 1300 Kg

initial speed of the automobile in north direction= 7.20 j m/s

final speed of the automobile in west direction = -6.50 i m/s

now,

change in momentum

\Delta P = m (v_f - v_i)

\Delta P = 1300\times (-6.50 \hat{i} - 7.20 \hat{j})

\Delta P = 1300\times \sqrt{(-6.50)^2 + (-7.20)^2}

\Delta P = 1300\times 9.7

\Delta P = 12610\ kg.m/s

now, direction calculation

 \theta = tan^{-1}(\dfrac{7.2}{6.5})

 \theta = tan^{-1}(1.1076)

 \theta = 47.92^0

direction of the car is 48° in south west direction.

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