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DiKsa [7]
3 years ago
5

You are sitting in a car that isn't moving; suddenly, the car quickly accelerates. your body seems to be pushed back against the

seat. which word best explains why your body seemed to be pushed backward against the seat?
Physics
2 answers:
Amiraneli [1.4K]3 years ago
8 0
According to the Law of Inertia, our upper body was in rest and it wanted to remain in that condition.....
goldenfox [79]3 years ago
3 0

Explanation :

When the car accelerates, our body pushed backward against the seat. This effect is due to inertia.

When the car starts suddenly, our feet also comes in motion. But the rest body is still at rest.

Inertia is the property of a body which opposes its state of rest or state of motion.

In this case, the inertia of the passenger resists the motion of the car. So, he pushed backwards as the car started.  

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A box is being dragged with a horizontal force of 65 N for 12 meters. If there is a force of friction acting on it
asambeis [7]

Answer:

A. 780 J

B. 120 J

C. 660 J

Explanation:

From the question given above the following data were obtained:

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

A. Determination of the work done by the dragging force.

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Workdone (Wd) by dragging force =?

Wd = Fₔ × s

Wd = 65 × 12

Wd = 780 J

Therefore, the work done by the dragging force is 780 J

B. Determination of the work done by friction.

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

Workdone (Wd) by friction =?

Wd = Fբ × s

Wd = 10 × 12

Wd = 120 J

Therefore, the work done by friction is 120 J

C. Determination of the net work done on the box.

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

Net work done (Wd) =?

Next, we shall determine the net force acting on the box. This can be obtained as follow:

Dragging force (Fₔ) = 65 N

Force of friction (Fբ) = 10 N

Net force (Fₙ) =?

Fₙ = Fₔ – Fբ

Fₙ = 65 – 10

Fₙ = 55 N

Thus, the net force acting on the box is 55 N

Finally, we shall determine the net work done on the box as follow:

Distance (s) = 12 m

Net force (Fₙ) = 55 N

Net work done (Wd) =?

Wd = Fₙ × s

Wd = 55 × 12

Wd = 660 J

Therefore, the net work done on the box is 660 J

4 0
3 years ago
In diving to a depth of 248 m, an elephant seal also moves 296 m due east of his starting point. What is the magnitude of the se
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Answer:

The displacement is 386.16m

Explanation:

A seal dives to a depth of 248m. To find displacement, we must calculate the resultant vectors which will give us the displacement

R= sqrt(vector1+vector2)

Since this is a right angle triangle

R= sqrt(248^2 + 296^2)

R= sqrt(149120)

R= 386.16m

Displacement = 386.16m

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Answer:

the foiley like color doesn't absorb the heat it bounces off of it. it would be much better to have a black blanket

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