One shoe has a pointed heel that has a small cross sectional area, and another shoe has a broad heel with a large cross sectiona
1 answer:
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Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass,
Area of cross section,
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
Weight of the object = drag force
R = W
or
Where
is the density of air = 1.225 kg/m³
C is drag coefficient
So,
So, the drag coefficient is 1.01.
Answer:
Explanation:
means initial angular velocity, which is 0 rev/min
means final angular velocity, which is
t means time t= 3.20 s
one revolution is equivalent to 2πrad so the final angular velocity is:
= (2π/60) *2.513*10^{4} rad/s
= 2628.5 rad/s
so the angular acceleration, α will be:
α = 2628.5 rad/s / 3.20 s
so the rotational motion about a fixed axis is:
+ 2αΔTita where ΔTita is the angle in radians
so now find the ΔTita the subject of the formula
ΔTita =
Answer:
0.336 rad/s
Explanation:
= Angular speed of the turntable = -0.2 rad/s
R = Radius of turntable = 2.9 m
I = Moment of inertia of turntable =
M = Mass of turn table = 53 kg
= Magnitude of the runner's velocity relative to the earth = 3.6 m/s
As the momentum in the system is conserved we have
The angular velocity of the system if the runner comes to rest relative to the turntable which is the required answer is 0.336 rad/s