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Readme [11.4K]
3 years ago
14

Una banda de rock toca en un nivelde sonido de 80 dB ¿Cuál es laintensidad de ese sonido?​

Physics
1 answer:
BabaBlast [244]3 years ago
4 0
Nsnshsjsnsn nsnsnsnssjsins
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Psychology
Igoryamba

Answer:

True

Explanation:

8 0
3 years ago
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While on stage introducing the iPhone, Steve jobs walked 3 meters to the right, 9 meters to the left, 7 meters to the right, and
Y_Kistochka [10]

Answer:

Hey

The distance is easy, just add 3+9+7+9.

Answer <em>28m</em>

Distance is not to be confused with displacement (the total distance from your starting point).

<em>Wbob1314</em>

7 0
2 years ago
g Vector has a magnitude of 10.9 units and points due west. Vector points due north. (a) What is the magnitude of if + has a mag
NARA [144]

Answer:

a. 11.3 units

b. 46.031°

c. 11.3 units

d. 46.03°

Explanation:

a. magnitude

B = \sqrt{R^{2}-A^{2}  }

= √15.7² - 10.9²

= √127.68

= 11.3 units

b. direction

θ = cos⁻¹(10.9units/15.7 units)

= 46.031⁰ north of west

c. thge magnitude at 15.7 units is the same as solution a above

15.7² = 10.9² + B²

B = 11.3 units.

d. the direction is same as  answer b.

θ = 46.031°

but the vector faces south of west

3 0
3 years ago
A thin block of soft wood with a mass of 0.080 kg rests on a horizontal frictionless surface. A bullet with a mass of 4.67 g is
Licemer1 [7]

Answer:

(a) 222.126 m/s.

(b) KEi = 837.8 J, KEf = 308.81 J

Explanation:

(a)

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = mv+m'v'................ equation 1

Where m = mass of block, m' = mass of bullet, u = initial velocity of block, u' = initial velocity of bullet, v = final velocity of block, v' = final velocity of bullet.

make v' the subject of the equation,

v' = [(mu+m'u')-mv]/m'.................... Equation 2

Given: m = 0.08 kg, m' = 4.67 g = 0.00467 kg, u = 0 m/s (at rest), u' = 599 m/s, v = 22 m/s.

Substitute into equation 2

v' = [(0.08×0)+(0.00467×599)-(0.08×22)]/0.00467

v' = (2.79733-1.76)/0.00467

v' = 1.03733/0.00467

v' = 222.126 m/s.

Hence the speed at which the bullet exit the block = 222.126 m/s.

(b)

Initial kinetic energy of the system

KEi = 1/2mu² + 1/2m'u'² = 1/2(0.08×0²) + 1/2(0.00467×599²)

KEi = 0+837.8 = 837.8 J.

Final kinetic energy of the system

KEf = 1/2mv² + 1/2m'v'²

KEf = 1/2(0.08×22²) + 1/2(0.00467×222.126²)

KEf = 19.36+115.21 = 308.81 J

7 0
3 years ago
Brainliest?
Tpy6a [65]

The answer is D) Gravity is dependent on mass and strong nuclear force is not.

pls mark me brainliest

5 0
3 years ago
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