Answer:
1.5 kgms⁻¹
Explanation:
Momentum can be defined as "<em>mass in motion</em>."
The amount of momentum that an object has is dependent upon two factors
- mass of the moving object
when there is a change in the velocity , it creates a change in momentum also
when we consider that we can mathematically show this,In terms of an equation,
Change in momentum (ΔΡ) = m(Δv)
where (Δv) - change in velocity
<em>(Δv) = final velocity - initial velocity</em>
Change in momentum (ΔΡ) = m(Δv)
= 0.1×([55-40])
= 1.5 kgms⁻¹
Is there options for this??
Answer:
p = 1.16 10⁻¹⁴ C m and ΔU = 2.7 10 -11 J
Explanation:
The dipole moment of a dipole is the product of charges by distance
p = 2 a q
With 2a the distance between the charges and the magnitude of the charges
p = 1.7 10⁻⁹ 6.8 10⁻⁶
p = 1.16 10⁻¹⁴ C m
The potential energie dipole is described by the expression
U = - p E cos θ
Where θ is the angle between the dipole and the electric field, the zero value of the potential energy is located for when the dipole is perpendicular to the electric field line
Orientation parallel to the field
θ = 0º
U = 1.16 10⁻¹⁴ 1160 cos 0
U1 = 1.35 10⁻¹¹ J
Antiparallel orientation
θ = 180º
cos 180 = -1
U2 = -1.35 10⁻¹¹ J
The difference in energy between these two configurations is the subtraction of the energies
ΔU = | U1 -U2 |
ΔU = 1.35 10-11 - (-1.35 10-11)
ΔU = 2.7 10 -11 J
Answer: The horizontal location of the plane will BE OVER THE BOMB
Explanation:
As soon as the bomb was dropped, the bomb will fall under gravity (free fall) and the location of the plane continues to increase horizontally till the bomb reaches the ground which is a falling distance to be travelled by the bomb at 9.8m/s²
