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3 years ago

Please help!!A camera lens 13.3 cm from a

Physics

1 answer:

kumpel [21]3 years ago

7 0

Answer:

f=1.92 cm

If ans is correct reply for explanation.

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All types of mass movement are caused by the force of

PilotLPTM [1.2K]

Answer:

Mass and Acceleration

Explanation:

The typical Force equation is:

F = ma

where m = mass, and a=acceleration.

6 0

3 years ago

Read 2 more answers

A car accelerates at a rate of 3.0 m/s2. If its original speed is 8.0 m/s, how many seconds will it take the car to reach a fina

V125BC [204]

Answer:

5.7 s

Explanation:

Given:

a = 3.0 m/s²

v₀ = 8.0 m/s

v = 25.0 m/s

Find: t

v = at + v₀

25.0 m/s = (3.0 m/s²) t + 8.0 m/s

t ≈ 5.7 s

5 0

3 years ago

What is the power involved in lifting a 1.0-kg object 1.0 m in 1.0 s??

MAVERICK [17]

Mass = 1kg
Distance = 1m
Time = 1s
Force= Mass x Acceleration due to graviy
          = 1 x 9.8 = 9.8
Velocity = Distance / time
              = 1 / 1 =1m/s
Power = Force x velocity
           = 9.8 x 1 = 9.8 W

5 0

3 years ago

Suppose that you purchased a water bed with the dimensions 2.55 m Ã 2.53 dm Ã 245 cm. what mass of water does this bed contain

Nadya [2.5K]

dimensions of the bed is given as

$length = 2.55 m$

$thickness = 2.53 dm = 0.253 m$

$width = 245 cm = 2.45 m$

now the volume of the bed is given as

$V = 2.55 * 0.253 * 2.45 m^3$

$V = 1.581m^3$

now the mass of water in it is given as

$mass = density * volume$

$mass = 1000* 1.581$

$mass = 1581 kg$

<em>so it will contain 1581 kg mass in it</em>

6 0

3 years ago

A stone is tied to a string and whirled at constant speed in a horizontal circle. The speed is then doubled without changing the

Tanya [424]

Answer:

Afterward the magnitude of the acceleration of the stone is four times as great

Explanation:

A stone tied to a string and whirled at a constant speed in a horizontal circle will have a centripetal acceleration given by

$a = \frac{v^{2} }{r}$

Where $a$ is the centripetal acceleration

$v$ is the speed

and $r$ is the radius of the circle

Here, the radius of the circle is the length of the string.

Now, from the question

The speed is then doubled without changing the length of the string,

Let the new speed be $v_{2}$ , that is

$v_{2} = 2v$

and without changing the length of the string means radius $r$ is constant.

To determine the magnitude of the acceleration of the stone afterwards,

Let the new acceleration be $a_{2}$ .

Then we can write that

$a_{2} = \frac{v_{2}^{2} }{r}$

From

$a = \frac{v^{2} }{r}$

$v = \sqrt{ar}$

Recall that

$v_{2} = 2v$

∴ $v_{2} = 2\sqrt{ar}$

Now, we will put the value of $v_{2}$ into

$a_{2} = \frac{v_{2}^{2} }{r}$

Then,

$a_{2} = \frac{(2\sqrt{ar}) ^{2} }{r}$

$a_{2} = \frac{4ar }{r}$

$a_{2} = 4a$

The new magnitude of the acceleration of the stone is four times the initial acceleration.

Hence,

Afterward the magnitude of the acceleration of the stone is four times as great

3 0

3 years ago