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3 years ago

Please help!!A camera lens 13.3 cm from a

Physics

1 answer:

kumpel [21]3 years ago

7 0

Answer:

f=1.92 cm

If ans is correct reply for explanation.

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The stored energy an object has due to its MOTION system transformation

jekas [21]

Answer:A

Explanation:

Kinetic energy is energy caused by motion.a body in motion possess kinetic energy

3 0

3 years ago

A particle moving along a straight line is subjected to a deceleration ???? = (−2???? 3 ) m/???? 2 , where v is in m/s. If it ha

dlinn [17]

Answer:

(a). The velocity is 0.099 m/s.

(b). The position is 19.75 m.

Explanation:

Given that,

The deceleration is

$a=(-2v^3)\ m/s^2$

We need to calculate the velocity at t = 25 s

The acceleration is the first derivative of velocity of the particle.

$a=\dfrac{dv}{dt}$

$\dfrac{dv}{dt}=-2v^3$

$\dfrac{dv}{-v^3}=2dt$

On integrating

$int{\dfrac{dv}{-v^3}}=\int{2dt}$

$\dfrac{1}{2v^2}=2t+C$

$v^2=\dfrac{1}{4t+2C}$ ....(I)

At t = 0, v = 10 m/s

$10^2=\dfrac{1}{4\times0+2C}$

$C=\dfrac{1}{200}$

Put the value of C in equation (I)

$v^2=\dfrac{1}{4\times25+2\times\dfrac{1}{200}}$

$v=\sqrt{\dfrac{1}{4\times25+2\times\dfrac{1}{200}}}$

$v=0.099\ m/s$

The velocity is 0.099 m/s.

(b). We need to calculate the position at t = 25 sec

The velocity is the first derivative of position of the particle.

$\dfrac{ds}{dt}=v$

On integrating

$\int{ds}=\int(\sqrt{\dfrac{200}{800t+1}})dt$

$s=\dfrac{\sqrt{200}\times2\sqrt{800t+1}}{800}+C'$

At t = 0, s = 15 m

$15=\dfrac{200}{800}+C'$

$C'=15-\dfrac{200}{800}$

$C'=14.75$

Put the value in the equation

$s=\dfrac{\sqrt{200}\times2\sqrt{800\times25+1}}{800}+14.75$

$s=19.75\ m$

The position is 19.75 m.

Hence, (a). The velocity is 0.099 m/s.

(b). The position is 19.75 m.

3 0

3 years ago

12. The red light emitted by a He-Ne laser has a wavelength of 6.33 x 10^-7 m in the air and travels 3.0 x 10^8 m/s. Find the fr

Ymorist [56]

Answer:

f = 4.76 × 10^14 Hz

Frequency of the laser light f = 4.76 × 10^14 Hz

Explanation:

Given;

wavelength = 6.33 x 10^-7 m

Speed of light v = 3.0 x 10^8 m/s.

Frequency of the laser light f

= speed of light/wavelength

Substituting the given values;

f = 3.0 x 10^8 m/s ÷ 6.33 x 10^-7 m

f = 4.76 × 10^14 Hz

Frequency of the laser light f = 4.76 × 10^14 Hz

4 0

4 years ago

A water wave traves with a length of 10 meters and a frequency of 30 hertz, what is the velocity of the wave?

UNO [17]

Answer: 300 m/s

Explanation:

Given that:

length of water wave (λ) = 10 metres

Frequency of water wave (F) = 30 Hertz

Velocity of water wave (V) = ?

The velocity of a wave is the distance covered by the wave in one second. It is measured in metre per second, and represented by the symbol V. It is related to frequency and wave length by the formula: V = F λ

V = 30 Hertz x 10 metres

V = 300 m/s

Thus, the velocity of the water wave is 300 m/s

4 0

3 years ago

A 58.0-kg projectile is fired at an angle of 30.0° above the horizontal with an initial speed of 140 m/s from the top of a cliff

strojnjashka [21]

(a) $6.43\cdot 10^5 J$

The total mechanical energy of the projectile at the beginning is the sum of the initial kinetic energy (K) and potential energy (U):

$E=K+U$

The initial kinetic energy is:

$K=\frac{1}{2}mv^2$

where m = 58.0 kg is the mass of the projectile and $v=140 m/s$ is the initial speed. Substituting,

$K=\frac{1}{2}(58 kg)(140 m/s)^2=5.68\cdot 10^5 J$

The initial potential energy is given by

$U=mgh$

where g=9.8 m/s^2 is the gravitational acceleration and h=132 m is the height of the cliff. Substituting,

$U=(58.0 kg)(9.8 m/s^2)(132 m)=7.5\cdot 10^4 J$

So, the initial mechanical energy is

$E=K+U=5.68\cdot 10^5 J+7.5\cdot 10^4 J=6.43\cdot 10^5 J$

(b) $-1.67 \cdot 10^5 J$

We need to calculate the total mechanical energy of the projectile when it reaches its maximum height of y=336 m, where it is travelling at a speed of v=99.2 m/s.

The kinetic energy is

$K=\frac{1}{2}(58 kg)(99.2 m/s)^2=2.85\cdot 10^5 J$