Answer:
time=4, answer choice A
time=5.5, answer choice B
Explanation:
This is taken from the kinematic equation, v=vo+(1/2)at^2
Velocity at time 4 = 30+(2.5)(4)^2
Velocity at time 5.5 = 30+(2.5)(5.5)^2
Velocity at time 4 seconds = 70 m/s
Velocity at time 5.5 seconds = 105.63 m/s
Answer:
2.47 m
Explanation:
Let's calculate first the time it takes for the ball to cover the horizontal distance that separates the starting point from the crossbar of d = 52 m.
The horizontal velocity of the ball is constant:
and the time taken to cover the horizontal distance d is
So this is the time the ball takes to reach the horizontal position of the crossbar.
The vertical position of the ball at time t is given by
where
is the initial vertical velocity
g = 9.8 m/s^2 is the acceleration of gravity
And substituting t = 2.56 s, we find the vertical position of the ball when it is above the crossbar:
The height of the crossbar is h = 3.05 m, so the ball passes
above the crossbar.
When blue litmus paper is dipped in acid the paper turns red.
hope this helps :)
From Newton’s Third Law, the Law of Conservation of Momentum for an elastic collision is derived as m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.
<h3>
Newton's third law</h3>
This law states that action and reaction are equal and opposite. That is the force applied to an object is equal to the reaction received by the object.
F₁₂ = -F₂₁
m₁a₁ = -m₂a₂
m₁v₁/t = -m₂v₂/t
m₁v₁ = -m₂v₂
m₁v₁ + m₂v₂ = 0
<h3>For an elastic collision involving two objects</h3>
The sum of the initial momentum must be equal to sum of final momentum.
- let initial velocity = u
- let final velocity = v
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Thus, from Newton’s Third Law, the Law of Conservation of Momentum for an elastic collision is derived as m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.
Learn more about conservation of linear momentum here: brainly.com/question/7538238