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Taya2010 [7]
3 years ago
12

What would happen if a proton were added to the nucleus of the atom? (Check all that apply)

Physics
1 answer:
wel3 years ago
4 0

If a proton were added to the nucleus of an atom . . .

-- It would become a different atom (an atom of a different element) .

-- It would add 1 to the atomic mass.

-- Its charge would increase by +1 .

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Does anyone know this one? Thanks
Inessa [10]

Answer:

3.844\,*\,10^5

So a=3.844 and b=5

Explanation:

Scientific notation requests to write a number using powers of ten as a factor accompanying a real number (a) between 1 and smaller than 10 that contains the digits to exactly represent the original number. So in this case, the number 384,400 can be written as:

384,400=3.844 \,*\,100,000= 3.844 \,*\,10^5

with a=3.844, and "5" as the exponent of ten (so b=5)

6 0
3 years ago
HELP!!! Why is plasma considered the most common state of matter in the universe?
olasank [31]

Clue : There is plasma in sun

4 0
2 years ago
Read 2 more answers
A coil of wire with 100. circular turns of radius 8.00 cm is in a uniform magnetic field along the axis of the coil. The resista
andreyandreev [35.5K]
I think Im gonna have to go with C 6.00 T/s but Im not sure
6 0
3 years ago
NEED THIS DONE ASAP HELP
ExtremeBDS [4]

Answer: Exercise Physiology

Explanation:

4 0
2 years ago
In a golf ball game, a person hits the golf ball with a club. The club is in contact with the ball, which is initially at rest,
Anon25 [30]

Answer:

F=4040.81 N

Explanation:

Given that

Time ,t= 2.45 ms

Mass ,m= 0.055 kg

v= 1.8 x 10² m/s = 180 m/s

We know that rate of change in the linear momentum is known as force.

Momentum P = m v

F=\dfrac{dP}{dt}

Therefore force F

F=\dfrac{\Delta P}{\Delta t}

F=\dfrac{0.055\times 180}{2.45\times 10^{-3}}\ N

F=4040.81 N

Therefore force on the ball will be 4040.81 N

6 0
3 years ago
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