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earnstyle [38]
4 years ago
11

During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t

op of the science building. Determine distance the ball has traveled after falling for 1.0 second, ignoring air resistance and given the gravitational acceleration of 9.8 m/sec2. A) 4.9 m B) 11 m C) 20 m D) 32 m
Physics
1 answer:
nydimaria [60]4 years ago
8 0

Given that,

mass of ball , m =11 lbs

Time , t = 1.0 seconds

Acceleration , a = 9.8 m/s²

Distance , s = ?

Since, we know that,

S = Vi *t + 1/2 at²

Since initial velocity is zero in this case (ball was at state of rest before falling to the ground)

S = 1/2 *9.8 * (1)²

S = 4.9 m

The distance covered by ball after one second will be 4.9 m.

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__ is the second most abundant element in Earth’s crust. It is found in ___, and ___; and in _ which is used to make pottery.
lianna [129]

Answer:

silicon is the second most abundant element in Earth’s crust. It is found in the sun and stars; and in clay which is used to make pottery.

Explanation:

6 0
3 years ago
Is O2 classified as a compound?
dybincka [34]

Answer: NO.

Explanation: Oxygen is not a compound. It has only one element in it.

3 0
3 years ago
A ball thrown vertically upward is caught by the thrower after 2.93 s. Find the initial velocity of the ball. The acceleration o
almond37 [142]

Answer:

The initial velocity of the ball is 28.714 m/s

Explanation:

Given;

time of flight of the ball, t = 2.93 s

acceleration due to gravity, g = 9.8 m/s²

initial velocity of the ball, u = ?

The initial velocity of the ball is given by;

v = u + (-g)t

where;

v is the final speed of the ball at the given time, = 0

g is negative because of upward motion

0 = u -gt

u = gt

u = (9.8 x 2.93)

u = 28.714 m/s

Therefore, the initial velocity of the ball is 28.714 m/s

7 0
3 years ago
1. A 6-volt battery produces a current of 0.5 amps. What is the power in the circuit?
allochka39001 [22]

Answer:

hope this will help you

have a great day

Explanation:

please mark me as the brainliest

8 0
2 years ago
What is the kinetic energy of a 200 kg satellite as it follows a circular orbit of radius 8x106m around the earth?
motikmotik
Given the equation for the Speed of a Satellite

v = SqRt{Gravitational Constant}{Mass of Earth} divided by the radius given in your problem

we have:


(square root whole term on right side)

v = G Me
———
r


so. (6.67x10^-11)(5.97x10^24)
___________________
(8.0x10^6)


v = 7055 m/s (which is reasonable)


so utilize the Kinetic Energy Formula


KE = 1/2mv^2


KE = 1/2(200)(7055)^2


KE = 4.977x10^9 J


4 0
3 years ago
Read 2 more answers
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