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earnstyle [38]
4 years ago
11

During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t

op of the science building. Determine distance the ball has traveled after falling for 1.0 second, ignoring air resistance and given the gravitational acceleration of 9.8 m/sec2. A) 4.9 m B) 11 m C) 20 m D) 32 m
Physics
1 answer:
nydimaria [60]4 years ago
8 0

Given that,

mass of ball , m =11 lbs

Time , t = 1.0 seconds

Acceleration , a = 9.8 m/s²

Distance , s = ?

Since, we know that,

S = Vi *t + 1/2 at²

Since initial velocity is zero in this case (ball was at state of rest before falling to the ground)

S = 1/2 *9.8 * (1)²

S = 4.9 m

The distance covered by ball after one second will be 4.9 m.

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Tom [10]
The answer is 2728283 69
4 0
3 years ago
PLZ HELP ME NOW PLZ I NEED THE ANSWER NOW. which statement describes the correct charges of subatomic particles?
Lapatulllka [165]
Are there choices that come with this question?

6 0
3 years ago
Read 2 more answers
A 128.0-N carton is pulled up a frictionless baggage ramp inclined at 30.0∘above the horizontal by a rope exerting a 72.0-N pull
Elden [556K]

Answer:

(A) 374.4 J

(B) -332.8 J

(C) 0 J

(D) 41.6 J

(E)  351.8 J

Explanation:

weight of carton (w) = 128 N

angle of inclination (θ) = 30 degrees

force (f) = 72 N

distance (s) = 5.2 m

(A) calculate the work done by the rope

  • work done = force x distance x cos θ
  • since the rope is parallel to the ramp the angle between the rope and

        the ramp θ will be 0

       work done = 72 x 5.2 x cos 0

       work done by the rope = 374.4 J

(B) calculate the work done by gravity

  • the work done by gravity = weight of carton x distance x cos θ
  • The weight of the carton = force exerted by the mass of the carton = m x g
  • the angle between the force exerted by the weight of the carton and the ramp is 120 degrees.

      work done by gravity = 128 x 5.2  x cos 120

      work done by gravity = -332.8 J

(C) find the work done by the normal force acting on the ramp

  • work done by the normal force = force x distance x cos θ
  • the angle between the normal force and the ramp is 90 degrees

       

         work done by the normal force = Fn x distance x cos θ

         work done by the normal force = Fn x 5.2 x cos 90

         work done by the normal force = Fn x 5.2 x 0

         work done by the normal force = 0 J

(D)  what is the net work done ?

  • The net work done is the addition of the work done by the rope,       gravitational force and the normal force

     net work done = 374.4 - 332.8 + 0 =  41.6 J  

(E) what is the work done by the rope when it is inclined at 50 degrees to the horizontal

  • work done by the rope= force x distance x cos θ
  • the angle of inclination will be 50 - 30 = 20 degrees, this is because the ramp is inclined at 30 degrees to the horizontal and the rope is inclined at 50 degrees to the horizontal and it is the angle of inclination of the rope with respect to the ramp we require to get the work done by the rope in pulling the carton on the ramp

work done = 72 x 5.2 x cos 20

work done = 351.8 J

5 0
4 years ago
In a calorimetry experiment, three samples A, B, and C with TA> TB> Tc are placed in thermal contact. When the samples hav
zaharov [31]

Answer:

e. TA>T>Tc

Explanation:

a) In this case, we cannot say for sure QA>QB>QC. This is because the magnitude of the heat flow will depend on the specific heat and the mass of each sample. Due to the equation:

Q=mC_{p}(T_{f}-T_{0})

if we did an energy balance of the system, we would get that>

QA+QB+QC=0

For this equation to be true, at least one of the heats must be negative. And one of the heats must be positive.

We don't know either of them, so we cannot determine if this statement is true.

b) We can say for sure that QA<0, because when the two samples get to equilibrum, the temperatrue of A must be smaller than its original temperature. Therefore, it must have lost heat. But we cannot say for sure if QB<0 because sample B could have gained or lost heat during the process, this will depend on the equilibrium temperature, which we don't know. So we cannot say for sure this option is correct.

c) In this case we don't know for sure if the equilibrium temperature will be greater or smaller than TB. This will depend on the mass and specific heat of the samples, just line in part a.

d) is not complete

e) We know for sure that A must have lost heat, so its equilibrium temperature must be smaller than it's original temperature. We know that C must have gained heat, therefore it's equilibrium temperature must be greater than it's original temperature, so TA>T>Tc must be true.

3 0
3 years ago
A minivan sells for 33,200 dollars. Give the price of the minivan in a) kilodollars and megadollars
amm1812
The prefix of a unit could give you a hint on its extent with respect to the base unit. In this case, the base unit is money in terms of dollars. When you say kilodollars, that would be 1,000 times as large as a dollar. Hence,

33,200 dollars * 1 kilodollar/ 1,000 dollars =  33.2 kilodollars

When you say megadollars, that would be a million times as large as a dollar. Hence,

33,200 dollars * 1 megadollar/1,000,000 dollars = 0.0332 megadollars

6 0
4 years ago
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