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earnstyle [38]
3 years ago
11

During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t

op of the science building. Determine distance the ball has traveled after falling for 1.0 second, ignoring air resistance and given the gravitational acceleration of 9.8 m/sec2. A) 4.9 m B) 11 m C) 20 m D) 32 m
Physics
1 answer:
nydimaria [60]3 years ago
8 0

Given that,

mass of ball , m =11 lbs

Time , t = 1.0 seconds

Acceleration , a = 9.8 m/s²

Distance , s = ?

Since, we know that,

S = Vi *t + 1/2 at²

Since initial velocity is zero in this case (ball was at state of rest before falling to the ground)

S = 1/2 *9.8 * (1)²

S = 4.9 m

The distance covered by ball after one second will be 4.9 m.

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Ilia_Sergeevich [38]

Initial momentum = 2 * m v

so if 1 ball popped out with 2 v momentum would be conserved

but the initial kinetic energy of the two balls is

1/2 m v^2 + 1/2 m v^2 = m v^2

But the kinetic energy of one ball with twice the speed would be

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8 0
2 years ago
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Answer:

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5 0
2 years ago
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2 years ago
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8 0
3 years ago
Read 2 more answers
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